Elements of AlgebraA. S. Barnes, 1842 - 358 sider |
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Resultat 1-5 av 66
Side 16
... third degree and homogeneous . 8a3 - 4ab + c is not homogeneous . 9 27. A vinculum or bar or a parenthesis ( ) , is used to express that all the terms of a polynomial are to be considered to- gether . Thus , a + b + cxb , or ( a + bxc ) ...
... third degree and homogeneous . 8a3 - 4ab + c is not homogeneous . 9 27. A vinculum or bar or a parenthesis ( ) , is used to express that all the terms of a polynomial are to be considered to- gether . Thus , a + b + cxb , or ( a + bxc ) ...
Side 34
... third monomial , which , multiplied by 8a3 , will produce 72a5 . The co - efficient of a in the quotient must be such a number as being multiplied by 8 shall give 72 , the co - efficient of a in the dividend ; and the exponent of a in ...
... third monomial , which , multiplied by 8a3 , will produce 72a5 . The co - efficient of a in the quotient must be such a number as being multiplied by 8 shall give 72 , the co - efficient of a in the dividend ; and the exponent of a in ...
Side 38
... third polynomial called the quotient , which , multiplied by the divisor , shall produce the dividend . Hence , the dividend is the assemblage , after reduc- tion , of the partial products of each term of the divisor by each term of the ...
... third polynomial called the quotient , which , multiplied by the divisor , shall produce the dividend . Hence , the dividend is the assemblage , after reduc- tion , of the partial products of each term of the divisor by each term of the ...
Side 40
... third remark of Art . 45 , it appears that the term of the dividend affected with the highest exponent of the leading letter , and the term affected with the lowest exponent of the same letter , may each be derived without reduction ...
... third remark of Art . 45 , it appears that the term of the dividend affected with the highest exponent of the leading letter , and the term affected with the lowest exponent of the same letter , may each be derived without reduction ...
Side 42
... THIRD EXAMPLE .. Divide 95a - 73a2 + 56a4-25-59a3 by -3a2 + 5-11a - 7as 1st , rem . 2d . rem . 56a - 59a3-73a2 + 95a - 25 || 7a3 - 3a2 - 11a + 5 -35a3 + 15a2 + 55a - 25 0 . 8a - 5 GENERAL EXAMPLES . 1. Divide 18x2 by 9x . 2. 42 ALGEBRA .
... THIRD EXAMPLE .. Divide 95a - 73a2 + 56a4-25-59a3 by -3a2 + 5-11a - 7as 1st , rem . 2d . rem . 56a - 59a3-73a2 + 95a - 25 || 7a3 - 3a2 - 11a + 5 -35a3 + 15a2 + 55a - 25 0 . 8a - 5 GENERAL EXAMPLES . 1. Divide 18x2 by 9x . 2. 42 ALGEBRA .
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Elements of Algebra: Tr. from the French of M. Bourdon. Revised and Adapted ... Charles Davies Uten tilgangsbegrensning - 1835 |
Elements of Algebra: Translated from the French of M. Bourdon; Revised and ... Charles Davies Ingen forhåndsvisning tilgjengelig - 2017 |
Elements of Algebra: Translated From the French of M. Bourdon; Revised and ... Charles Davies Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
affected algebraic quantities arithmetical arithmetical means arithmetical progression arranged binomial cents co-efficient common difference common factor consequently contain contrary signs cube root decimal deduce denominator denote divide dividend division double product entire number enunciation equa equal equation becomes equation involving example expression extract the square figure find the values formula fourth fraction given number gives greater greatest common divisor greyhound Hence indeterminate inequality last term least common multiple less letters logarithm manner monomial multiplicand multiplied negative nth root number of terms obtain operation perfect square positive roots preceding problem progression proposed equation quotient reduced remainder result satisfy second degree second member second term square root substituted subtract suppose take the equation taken tens third tion transposing twice the product unity unknown quantity verified whence whole number
Populære avsnitt
Side 181 - C' then A is said to have the same ratio to B that C has to D ; or, the ratio of A to B is equal to the ratio of C to D.
Side 183 - D, we have — =— , (Art. 169) ; nj\ and by clearing the equation of fractions, we have BC=AD; that is, of four proportional quantities, the product of the two extremes is equal to the product of the two means.
Side 122 - These expressions may sometimes be simplified, upon the principle that, the square root of the product of two or more factors is equal to the product of the square roots of these factors; or, in algebraic language, V'abed . . . = i/a.
Side 181 - To express that the ratio of A to B is equal to the ratio of C to D, we write the quantities thus : A : B : : C : D ; and read, A is to B as C to D.
Side 114 - ... the entire part of the root sought. For example, if it were required to extract the square root of 665, we should find 25 for the entire part of the root, and a remainder of 40, which shows that 665 is not a perfect square. But is the square of 25 the greatest perfect square contained in 665 ? that is, is 25 the entire part of the root ? To prove this, we will first show that, the difference between the squares of two consecutive numbers, is equal to twice the less number augmented by unity.
Side 28 - Multiply each term of the multiplicand by each term of the multiplier, and add the partial products.
Side 33 - The square of the sum of two quantities is equal to the square of the first, plus twice the product of the first and second, plus the square of the second.
Side 267 - The logarithm of a number is the exponent of the power to which it is necessary to raise a fixed number, in order to produce the first number.
Side 146 - B, departed from different places at the same time, and travelled towards each other. On meeting, it appeared that A had travelled 18 miles more than B ; and that A could have gone B's journey in 15| days, but B would have been 28 days in performing A's journey. How far did each travel ? Ans.
Side 90 - If A and B together can perform a piece of work in 8 days, A and c together in 9 days, and B and c in 10 days, how many days will it take each person to perform the same work alone.