Euclid's Elements of Geometry, Bøker 1-6Henry Martyn Taylor The University Press, 1893 - 504 sider |
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Resultat 1-5 av 41
Side xii
... divided into two Parts . Proposition 32 of Euclid's text , which is a very special case of no great interest , has been replaced by a simple but important theorem in the theory of similar and similarly situate figures . The chief ...
... divided into two Parts . Proposition 32 of Euclid's text , which is a very special case of no great interest , has been replaced by a simple but important theorem in the theory of similar and similarly situate figures . The chief ...
Side 55
... divided into two parts by the perpen- dicular from the opposite vertex : prove that each part of the base is less than the adjacent side of the triangle . 3. A straight line drawn from the vertex of an isosceles triangle to any point in ...
... divided into two parts by the perpen- dicular from the opposite vertex : prove that each part of the base is less than the adjacent side of the triangle . 3. A straight line drawn from the vertex of an isosceles triangle to any point in ...
Side 63
... divided into two isosceles triangles . 4. Construct a triangle , having given the base , one of the angles at the base , and the sum of the sides . PROPOSITION 24 . If two sides of one triangle be PROPOSITION 23 . 63 EXERCISES. ...
... divided into two isosceles triangles . 4. Construct a triangle , having given the base , one of the angles at the base , and the sum of the sides . PROPOSITION 24 . If two sides of one triangle be PROPOSITION 23 . 63 EXERCISES. ...
Side 99
... divided into four triangles , which are all equal to one another . 3. If the sides BC , CA , AB of a triangle ABC be produced to A ' , B ' , C ' respectively , so that CA ' = BC , AB ' = CA , AB = BC ' , prove that the area of the ...
... divided into four triangles , which are all equal to one another . 3. If the sides BC , CA , AB of a triangle ABC be produced to A ' , B ' , C ' respectively , so that CA ' = BC , AB ' = CA , AB = BC ' , prove that the area of the ...
Side 122
... divided into one square IKLM and four equal right - angled triangles , ( 2 ) the square EFGH is divided into two squares EOQN , QPGR and four equal triangles , ( 3 ) all the triangles are equal to each other , ( 4 ) the square IL is ...
... divided into one square IKLM and four equal right - angled triangles , ( 2 ) the square EFGH is divided into two squares EOQN , QPGR and four equal triangles , ( 3 ) all the triangles are equal to each other , ( 4 ) the square IL is ...
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Vanlige uttrykk og setninger
ABCD AC is equal ADDITIONAL PROPOSITION angle ACB angle BAC angles ABC anharmonic arc ABC bisected centre of similitude chord circle ABC coincide Constr Coroll cut the circle describe a circle diagonal diameter draw equal angles equal circles equal to CD equiangular equimultiples Euclid EXERCISES exterior angle given circle given point given straight line given triangle greater harmonic range hypotenuse inscribed intersect Let ABC meet middle points opposite sides pair parallel parallelogram pencil pentagon perpendicular polygon PROOF Prop PROPOSITION 14 Ptolemy's Theorem quadrilateral radical axis radius rectangle contained required to prove respectively rhombus right angles shew sides BC Similarly square on AC straight line &c straight line drawn straight line joining subtend tangent theorem triangle ABC triangle DEF triangles are equal twice the rectangle vertices Wherefore
Populære avsnitt
Side 59 - Any two sides of a triangle are together greater than the third side.
Side 7 - An angle less than a right angle is called an acute angle; an angle greater than a right angle and less than two right angles is called an obtuse angle.
Side 68 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 144 - If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced...
Side 376 - To find a mean proportional between two given straight lines. Let AB, BC be the two given straight lines ; it is required to find a mean proportional between them. Place AB, BC in a straight line, and upon AC describe the semicircle ADC, and from the point B draw (9.
Side 135 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Side 76 - ... the same side together equal to two right angles ; the two straight lines shall be parallel to one another.
Side 305 - To inscribe, an equilateral and equiangular pentagon in a given circle. Let ABCDE be the given circle. It is required to inscribe an equilateral...
Side 424 - PROPOSITION 5. The locus of a point, the ratio of whose distances from two given points is constant, is a circle*.
Side 248 - If two straight lines within a circle cut one another, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other. Let the two straight lines AC, BD, within the circle ABCD, cut one another in the point E : the rectangle contained by AE, EC is equal to the rectangle contained by BE, ED.