Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids ; to which are Added, Elements of Plane and Spherical TrigonometryW.E. Dean, 1839 - 318 sider |
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Resultat 1-5 av 76
Side 18
... perpendicular to it . VIII . An obtuse angle is that which is greater than a right angle . IX . An acute angle is that which is less than a right angle . X. A figure is that which is enclosed by one or more boundaries . - The word area ...
... perpendicular to it . VIII . An obtuse angle is that which is greater than a right angle . IX . An acute angle is that which is less than a right angle . X. A figure is that which is enclosed by one or more boundaries . - The word area ...
Side 29
... perpendicular to a given straight line , of an unlimited length , from a given point without it . Let AB be a given straight line , which may be produced to any length both ways , and let C be a point without it . It is required to draw ...
... perpendicular to a given straight line , of an unlimited length , from a given point without it . Let AB be a given straight line , which may be produced to any length both ways , and let C be a point without it . It is required to draw ...
Side 62
... perpendicular falls , and the straight line intercepted between the perpendicular and the obtuse angle . Let ABC be an obtuse angled triangle , having the obtuse angle ACB , and from the point A let AD be drawn ( 12. 1. ) perpendicular ...
... perpendicular falls , and the straight line intercepted between the perpendicular and the obtuse angle . Let ABC be an obtuse angled triangle , having the obtuse angle ACB , and from the point A let AD be drawn ( 12. 1. ) perpendicular ...
Side 63
... perpendicular to BC ; then is BC the straight line between the perpendicular and the acute angle at B ; and it is manifest that ( 47. 1. ) AB3 + BC3 = AC2 + 2BC3 — AC2 + 2BC.BC . There- fore in every triangle , & c . Q. E. D. A PROP ...
... perpendicular to BC ; then is BC the straight line between the perpendicular and the acute angle at B ; and it is manifest that ( 47. 1. ) AB3 + BC3 = AC2 + 2BC3 — AC2 + 2BC.BC . There- fore in every triangle , & c . Q. E. D. A PROP ...
Side 64
... perpendicular to BC , and because BEA is a right angle , AB3 = ( 47. 1. ) BE3 + AE and AC - CE + AE ; where- fore AB + AC2 = BE + CE + 2AE " . But because the line BC is cut equally in D , and unequally in E , BE2 + CE2 = ( 9. 2. ) 2BD2 ...
... perpendicular to BC , and because BEA is a right angle , AB3 = ( 47. 1. ) BE3 + AE and AC - CE + AE ; where- fore AB + AC2 = BE + CE + 2AE " . But because the line BC is cut equally in D , and unequally in E , BE2 + CE2 = ( 9. 2. ) 2BD2 ...
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Vanlige uttrykk og setninger
ABC is equal ABCD altitude angle ABC angle ACB angle BAC angle EDF arch AC base BC bisected centre circle ABC circumference cosine cylinder demonstrated diameter draw equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater hypotenuse inscribed join less Let ABC Let the straight line BC magnitudes meet opposite angle parallel parallelogram parallelopipeds perpendicular polygon prism PROB produced proportional proposition Q. E. D. COR Q. E. D. PROP radius ratio rectangle contained rectilineal figure remaining angle segment semicircle shewn side BC sine solid angle solid parallelopipeds spherical angle spherical triangle square straight line AC THEOR third touches the circle triangle ABC triangle DEF wherefore