A Higher AlgebraGinn, 1891 - 521 sider |
Inni boken
Resultat 1-5 av 43
Side 17
... example , it is required to add m + n - p to a + b + c , the result will be a + b + c + ( m + n − p ) . 34. If , however , there are like terms in the expressions to be added , the like terms can be collected ; that is , every set of ...
... example , it is required to add m + n - p to a + b + c , the result will be a + b + c + ( m + n − p ) . 34. If , however , there are like terms in the expressions to be added , the like terms can be collected ; that is , every set of ...
Side 40
... example , ( p −4 ) — ( p − 6 ) − p − 4 − p + 6 = 2 and ( r + 3 ) — ( r− 1 ) = r + 3 NOTE . Since an ÷ an − r + 1 = 4 . - = 1 , and by the rule that ao = 1. Hence , any letter in the quotient may be omitted without affecting the ...
... example , ( p −4 ) — ( p − 6 ) − p − 4 − p + 6 = 2 and ( r + 3 ) — ( r− 1 ) = r + 3 NOTE . Since an ÷ an − r + 1 = 4 . - = 1 , and by the rule that ao = 1. Hence , any letter in the quotient may be omitted without affecting the ...
Side 43
... examples : ( 1 ) Divide x2 + 18x + 77 by x + 7 . x2 + 18x + 77x + 7 x2 + 7x 11x + 77 11x + 77 x + 11 NOTE . The student will notice that by this process we have in effect separated the dividend into two parts , x2 + 7x and 11x + 77 ...
... examples : ( 1 ) Divide x2 + 18x + 77 by x + 7 . x2 + 18x + 77x + 7 x2 + 7x 11x + 77 11x + 77 x + 11 NOTE . The student will notice that by this process we have in effect separated the dividend into two parts , x2 + 7x and 11x + 77 ...
Side 50
... examples : ( 1 ) Find the number for which x stands when 16x - 11 = 7x + 70 . First subtract 7x from both sides ( Ax . 2 ) , which gives 9x - 11 = 70 . Then add 11 to these equals ( Ax . 1 ) , which gives 9x = 81 . Divide both sides by ...
... examples : ( 1 ) Find the number for which x stands when 16x - 11 = 7x + 70 . First subtract 7x from both sides ( Ax . 2 ) , which gives 9x - 11 = 70 . Then add 11 to these equals ( Ax . 1 ) , which gives 9x = 81 . Divide both sides by ...
Side 54
... examples : ( 1 ) John has three times as many oranges as James , and they together have 32. How many has each ? Let then x be the number of oranges James has ; 3x is the number of oranges John has ; and x + 3x is the number of oranges ...
... examples : ( 1 ) John has three times as many oranges as James , and they together have 32. How many has each ? Let then x be the number of oranges James has ; 3x is the number of oranges John has ; and x + 3x is the number of oranges ...
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a₁ a²b² ab² ab³ algebraic arithmetical arithmetical mean arithmetical series arrangements ax² b₁ binomial c₁ called cent coefficient cologarithm column common factor common logarithms Complete the square complex number contain continued fraction convergent cube root d₁ decimal denominator denote determinant digits divided divisible divisor equal Exercise exponent expression Extract the square Find the H. C. F. Find the number Find the sum Find the value fraction harmonical series Hence imaginary integers integral less letters limit logarithm miles monomial Multiply negative number number of terms obtained positive integer quadratic quadratic equation quotient ratio remainder represent Resolve into factors result Simplify Solve square root subtract surd third trinomial unknown number variable whole number zero
Populære avsnitt
Side 303 - If the number is less than 1, make the characteristic of the logarithm negative, and one unit more than the number of zeros between the decimal point and the first significant figure of the given number.
Side 131 - A man leaves the half of his property to his wife, a sixth to each of his two children, a twelfth to his brother, and the remainder, amounting to $600, to his sister. What was the amount of his property ? 17.
Side 141 - A cask contains 12 gallons of wine and 18 gallons of water ; another cask contains 9 gallons of wine and 3 gallons of water. How many gallons must be drawn from each cask to produce a mixture containing 7 gallons of wine and 7 gallons of water?
Side 255 - If the product of two numbers is equal to the product of two others, either two may be made the extremes of a proportion and the other two the means. For, if ad = bc, then, dividing by bd, or / (л- с'- v / 316.
Side 161 - The sum of the two digits of a number is 6, and if the number is divided by the sum of the digits the quotient is 4. What is the number ? 19.
Side 461 - Form all the possible products of n elements each that can be formed by taking one, and only one, element from each row, and one, and only one, element from each column ; prefix to each of the products thus formed either...
Side 276 - The sum of the squares of the extremes of four numbers in arithmetical progression is 200, and the sum of the squares of the means is 136. What are the numbers ? 24.
Side 280 - Of three numbers in geometrical progression, the sum of the first and second exceeds the third by 3, and the sum of the first and third exceeds the second by 21. What are the numbers ? 15.
Side 418 - The coefficient pt of the fourth term with its sign changed is equal to the sum of the products of the roots taken three...
Side 255 - The equation ad = be gives be ad a = -у, b — — ; a с so that an extreme may be found by dividing the product of the means by the other extreme ; and a mean may be found by dividing the product of the extremes by the other mean.