The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected and Some of Euclid's Demonstrations are Restored. Also, to this Second Edition is Added the Book of Euclid's Data. In Like Manner Corrected. viz. the first six books, together with the eleventh and twelfth |
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Side 18
THEOR F one Gide of a triangle be produced , the exterior angle is greater than
either of the interior opposite angles . Let ABC be a triangle , and let its side BC
be produced to D. the exterior angle ACD is greater than either of the interior ...
THEOR F one Gide of a triangle be produced , the exterior angle is greater than
either of the interior opposite angles . Let ABC be a triangle , and let its side BC
be produced to D. the exterior angle ACD is greater than either of the interior ...
Side 31
each to each , to which the equal fides are opposite . therefore the Book I. angle
ACB is equal to the angle CBD , and becaufe the straight linem BC meets the two
straight lines AC , BD and makes the alternate angles ACB , CBD equal to one ...
each to each , to which the equal fides are opposite . therefore the Book I. angle
ACB is equal to the angle CBD , and becaufe the straight linem BC meets the two
straight lines AC , BD and makes the alternate angles ACB , CBD equal to one ...
Side 41
AC , AG upon the opposite G fides of AB , make with it at H the point A the
adjacent angles ecual to two right angles ; therefore CA is in the same K straight
lined with AG . for d . 14. I. the fame reason , AB and AH ale in the same straight
line ...
AC , AG upon the opposite G fides of AB , make with it at H the point A the
adjacent angles ecual to two right angles ; therefore CA is in the same K straight
lined with AG . for d . 14. I. the fame reason , AB and AH ale in the same straight
line ...
Side 222
11. opposite planes ALGF , CBHD , AH is cut into two equal parts by the plane
AGHC . therefore the D K folid AH is double of the prism which is contained by
the triN angles ALG , CBH . for the fame reason , because the folid C B AK is cut
by ...
11. opposite planes ALGF , CBHD , AH is cut into two equal parts by the plane
AGHC . therefore the D K folid AH is double of the prism which is contained by
the triN angles ALG , CBH . for the fame reason , because the folid C B AK is cut
by ...
Side 251
angle that is half of the parallelogram , these prisms are equal to Book XII . one
another ; therefore the prism having the parallelogram EBFG for its base , and the
straight line KH opposite to it , is equal to the 1.40.11 . prism having the triangle ...
angle that is half of the parallelogram , these prisms are equal to Book XII . one
another ; therefore the prism having the parallelogram EBFG for its base , and the
straight line KH opposite to it , is equal to the 1.40.11 . prism having the triangle ...
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The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have ... Robert Simson Uten tilgangsbegrensning - 1775 |
The Elements of Euclid: The Errors by which Theon, Or Others, Have Long ... Robert Simson Uten tilgangsbegrensning - 1827 |
The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ... Robert Simson Uten tilgangsbegrensning - 1781 |
Vanlige uttrykk og setninger
added alſo altitude angle ABC angle BAC baſe BC is given becauſe Book Book XI caſe circle circle ABCD circumference common cone cylinder Definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides firſt folid fore four fourth given angle given in poſition given in ſpecies given magnitude given ratio given ſtraight line greater Greek half join leſs likewiſe magnitude manner meet muſt oppoſite parallel parallelogram perpendicular plane priſm produced PROP proportionals Propoſition pyramid reaſon rectangle remaining right angles ſame ſecond ſegment ſhall ſhewn ſides ſimilar ſolid ſquare ſquare of AC taken THEOR theſe third thro triangle ABC wherefore whole
Populære avsnitt
Side 5 - Let it be granted that a straight line may be drawn from any one point to any other point.
Side 163 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 48 - If a straight line be divided into any two parts, the squares of the whole line, and of one of the parts, are equal to twice the rectangle contained by the whole and that part, together with the square of the other part. Let the straight line AB be divided into any two parts in the point C; the squares of AB, BC are equal to twice the rectangle AB, BC, together with the square of AC.
Side 73 - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle; and no straight line can be drawn from the extremity between that straight line and the circumference, so as not to cut the circle...
Side 105 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 3 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Side 167 - Similar triangles are to one another in the duplicate ratio of their homologous sides.
Side 54 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Side 47 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Side 37 - To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.