## The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected and Some of Euclid's Demonstrations are Restored. Also, to this Second Edition is Added the Book of Euclid's Data. In Like Manner Corrected. viz. the first six books, together with the eleventh and twelfth |

### Inni boken

Resultat 1-5 av 11

Side 41

I. the fame

angle DBC is equal to the angle FBA , each of them being a right angle , add to

each the angle ABC , E and the whole angle DBA is equal o to the whole FBC.

I. the fame

**reason**, AB and AH ale in the same straight line . and because theangle DBC is equal to the angle FBA , each of them being a right angle , add to

each the angle ABC , E and the whole angle DBA is equal o to the whole FBC.

Side 104

3. fore the angle BAE is equal é to the angle AED . for the same

the angles ABC , BCD , CDE is equal to the angle BAE or AED . therefore the pen

. tagon ABCDE is equiangular ; and it has been shewn that it is equilateral .

3. fore the angle BAE is equal é to the angle AED . for the same

**reason**, each ofthe angles ABC , BCD , CDE is equal to the angle BAE or AED . therefore the pen

. tagon ABCDE is equiangular ; and it has been shewn that it is equilateral .

Side 129

... because if there be any number of magnitudes equimultiples of as many , each

of each , whatever multiple one of them is of its part , the same multiple is the

whole of the wholeb . for the same

b .

... because if there be any number of magnitudes equimultiples of as many , each

of each , whatever multiple one of them is of its part , the same multiple is the

whole of the wholeb . for the same

**reason**L , and L , M , N are any equimultiplesb .

Side 167

... the same

sided figures AGHLB , CFEKD are equiangular , and because the figures AGHB ,

CFED are similar , GH is to HB , as FE to ED ; and as HB to HL , fo is ED to EK “ ...

... the same

**reason**, the angle ABL is equal to the angle CDK . therefore the fivesided figures AGHLB , CFEKD are equiangular , and because the figures AGHB ,

CFED are similar , GH is to HB , as FE to ED ; and as HB to HL , fo is ED to EK “ ...

Side 169

5 . bout the equal angles EBC , LGH are proportionals ; therefore the triangle

EBC is equiangular to the triangle LGH , and fimilar to it c . for the same А. M

the ...

5 . bout the equal angles EBC , LGH are proportionals ; therefore the triangle

EBC is equiangular to the triangle LGH , and fimilar to it c . for the same А. M

**reason**the triF angle ECDE B likewise is fiL G milar to the triangle LHK . thereforethe ...

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### Andre utgaver - Vis alle

The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have ... Robert Simson Uten tilgangsbegrensning - 1775 |

The Elements of Euclid: The Errors by which Theon, Or Others, Have Long ... Robert Simson Uten tilgangsbegrensning - 1827 |

The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ... Robert Simson Uten tilgangsbegrensning - 1781 |

### Vanlige uttrykk og setninger

added alſo altitude angle ABC angle BAC baſe BC is given becauſe Book Book XI caſe circle circle ABCD circumference common cone cylinder Definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides firſt folid fore four fourth given angle given in poſition given in ſpecies given magnitude given ratio given ſtraight line greater Greek half join leſs likewiſe magnitude manner meet muſt oppoſite parallel parallelogram perpendicular plane priſm produced PROP proportionals Propoſition pyramid reaſon rectangle remaining right angles ſame ſecond ſegment ſhall ſhewn ſides ſimilar ſolid ſquare ſquare of AC taken THEOR theſe third thro triangle ABC wherefore whole

### Populære avsnitt

Side 5 - Let it be granted that a straight line may be drawn from any one point to any other point.

Side 163 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Side 48 - If a straight line be divided into any two parts, the squares of the whole line, and of one of the parts, are equal to twice the rectangle contained by the whole and that part, together with the square of the other part. Let the straight line AB be divided into any two parts in the point C; the squares of AB, BC are equal to twice the rectangle AB, BC, together with the square of AC.

Side 73 - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle; and no straight line can be drawn from the extremity between that straight line and the circumference, so as not to cut the circle...

Side 105 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...

Side 3 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.

Side 167 - Similar triangles are to one another in the duplicate ratio of their homologous sides.

Side 54 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.

Side 47 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.

Side 37 - To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.