Euclid's Elements of geometry, the first three books (the fourth, fifth, and sixth books) tr. from the Lat. To which is added, A compendium of algebra (A compendium of trigonometry).1846 |
Inni boken
Resultat 1-5 av 48
Side 13
... perpendicular to a given right line ( AB ) , from a point ( C ) in the given line . From the given point C make both ... perpendicular to the given right line AB ( Def . 11. ) SCHOL . By the same method a perpendicular can be erected at ...
... perpendicular to a given right line ( AB ) , from a point ( C ) in the given line . From the given point C make both ... perpendicular to the given right line AB ( Def . 11. ) SCHOL . By the same method a perpendicular can be erected at ...
Side 14
... perpendicular to the given line . For draw CE and CF ; and in the triangles EDC and FDC , the sides EC , FC will be equal ( by Def . 15 ) but ED , FD are also equal ( by Constr . ) and CD com- mon ; therefore the angles EDC and FDC ...
... perpendicular to the given line . For draw CE and CF ; and in the triangles EDC and FDC , the sides EC , FC will be equal ( by Def . 15 ) but ED , FD are also equal ( by Constr . ) and CD com- mon ; therefore the angles EDC and FDC ...
Side 16
... perpendicular falls at the side of the acute angle . For , if it be possible , let BA , perpendicular to the right line ED fall at the side of the obtuse angle BCE , and the angle BAE will be less than the angle BCE ( by Def . 12 ) ...
... perpendicular falls at the side of the acute angle . For , if it be possible , let BA , perpendicular to the right line ED fall at the side of the obtuse angle BCE , and the angle BAE will be less than the angle BCE ( by Def . 12 ) ...
Side 18
... perpendicular , and the other not , BC will be less than BA . E A с B D For in the triangle ABC , since the angle BCA is right , BAC will be acute ( by Cor . Prop . 17 ) , therefore BC is opposite the less angle , and therefore is less ...
... perpendicular , and the other not , BC will be less than BA . E A с B D For in the triangle ABC , since the angle BCA is right , BAC will be acute ( by Cor . Prop . 17 ) , therefore BC is opposite the less angle , and therefore is less ...
Side 38
... an interval , describe a semicircle AEF ; through D draw DE perpendicular to AD , it will be the right line sought for . For draw BE . The square of BE , or of BA , it being equal to BE , is equal to the squares 38 FIRST BOOK .
... an interval , describe a semicircle AEF ; through D draw DE perpendicular to AD , it will be the right line sought for . For draw BE . The square of BE , or of BA , it being equal to BE , is equal to the squares 38 FIRST BOOK .
Vanlige uttrykk og setninger
absurd AC and CB AC by Prop AC is equal angle ABC angle equal angles by Prop arch bisected centre circumference co-efficient Const construct contained oftener diameter divided divisor double equal angles equal by Constr equal by Hypoth equal by Prop equal right lines equal to AC equal to twice equi-multiples equi-submultiples equiangular equilateral external angle fore fraction given angle given circle given line given right line given triangle greater half a right inscribed less multiplied opposite parallel parallelogram perpendicular PROPOSITION quantities quotient ratio rectangle under AC remaining angles remaining side right angle right line AB right line AC SCHOL segment semicircle side AC similar similarly demonstrated squares of AC submultiple subtract THEOREM tiple touches the circle triangle BAC twice the rectangle twice the square whole
Populære avsnitt
Side 20 - If two triangles have two sides of the one equal to two sides of the...
Side 30 - DE : but equal triangles on the same base and on the same side of it, are between the same parallels ; (i.
Side 209 - ... they have an angle of one equal to an angle of the other and the including sides are proportional; (c) their sides are respectively proportional.
Side 218 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 114 - To reduce fractions of different denominators to equivalent fractions having a common denominator. RULE.! Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Side 90 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Side 129 - In any proportion, the product of the means is equal to the product of the extremes.
Side 163 - Magnitudes are said to be in the same ratio, the first to the second and the third to the fourth, when, if any equimultiples whatever be taken of the first and third, and any equimultiples whatever of the second and fourth, the former equimultiples alike exceed, are alike equal to, or alike fall short of, the latter equimultiples respectively taken in corresponding order.
Side 215 - ... are to one another in the duplicate ratio of their homologous sides.
Side 160 - PROPOSITION XV. PROBLEM. To inscribe an equilateral and equiangular hexagon in a given circle. Let ABCDEF be the given circle.