Weekly problem papers, with notes. [With] Solutions1885 |
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Side 16
... Monday morning . No. 11 . PAPER VII . 1. Clear of fractions , and we get x3 ( a + b − c − d ) + 2x2 ( ab - - Then x = O is one root . ( 1 ) the equal roots to be - - cd ) + x { ab ( c + d ) − cd ( a + b ) } = 0 . Since two of the ...
... Monday morning . No. 11 . PAPER VII . 1. Clear of fractions , and we get x3 ( a + b − c − d ) + 2x2 ( ab - - Then x = O is one root . ( 1 ) the equal roots to be - - cd ) + x { ab ( c + d ) − cd ( a + b ) } = 0 . Since two of the ...
Side 18
... Monday morning . No. 1 . 6. Substitute and clear of fractions . :: ax + b + √ − 1 ay = ( cx + d ) § – cyn + √ − 1j ( cx + d ) n + cy§ } . Equate real and unreal parts . ..a ( a - c ) + cn.y = d & -b \ x.cny ( ac ) -dn S •• x { ( a ...
... Monday morning . No. 1 . 6. Substitute and clear of fractions . :: ax + b + √ − 1 ay = ( cx + d ) § – cyn + √ − 1j ( cx + d ) n + cy§ } . Equate real and unreal parts . ..a ( a - c ) + cn.y = d & -b \ x.cny ( ac ) -dn S •• x { ( a ...
Side 39
... Monday afternoon . No. 3 . 2. Tripos 1875 . Monday afternoon . No. 3 . 3. Tripos 1875 . Monday afternoon . No. 8 . 4 . A B C + + 2 2 75 A = ; . : 2 + c = .. tan tan ( 1/2 + c ) = cot ( bc ) ( b + c a ) tan 6+ c - − a ) tan 12 A ...
... Monday afternoon . No. 3 . 2. Tripos 1875 . Monday afternoon . No. 3 . 3. Tripos 1875 . Monday afternoon . No. 8 . 4 . A B C + + 2 2 75 A = ; . : 2 + c = .. tan tan ( 1/2 + c ) = cot ( bc ) ( b + c a ) tan 6+ c - − a ) tan 12 A ...
Side 40
... + b ) 8 . 2. Tripos 1875. Monday afternoon . No. 5 . 3 . a + b + c = 0 ; .. ( a + b ) 5 = − c5 ; - - a5 +65 + c5 5 = = ( a + b ) 5 a5 65 - 5 - ab { a3 + 2a2b + 2ab2 + 13 } . So - a3 +63 +03 3 = = ( a 40 SOLUTIONS OF.
... + b ) 8 . 2. Tripos 1875. Monday afternoon . No. 5 . 3 . a + b + c = 0 ; .. ( a + b ) 5 = − c5 ; - - a5 +65 + c5 5 = = ( a + b ) 5 a5 65 - 5 - ab { a3 + 2a2b + 2ab2 + 13 } . So - a3 +63 +03 3 = = ( a 40 SOLUTIONS OF.
Side 41
... Monday afternoon . No. 9 . Monday morning . No. 2 . 2 middle point of BC , G the C. of G. of the triangle . W. .. by symmetry the force will just be able to lift a corner of the triangle if applied at B or C. 7. Produce SY to meet S'P ...
... Monday afternoon . No. 9 . Monday morning . No. 2 . 2 middle point of BC , G the C. of G. of the triangle . W. .. by symmetry the force will just be able to lift a corner of the triangle if applied at B or C. 7. Produce SY to meet S'P ...
Vanlige uttrykk og setninger
a+b+c ABCD axis bisects the angle Cambridge centre chord circle round circle will go circum-circle Clifton College coef College conic const coordinates cos² cosec Crown 8vo denote diameter directrix draw Edition ellipse envelope equal equation Fcap fixed point geometrical given expression hyperbola inscribed circle intersect Join Let ABC Let the tangent locus Mathematics meet middle point Monday afternoon morning nine-point circle nth term orthocentre PAPER parabola parallel perpendicular plane Professor quadrilateral radical axis radius right angles shew shewn sides Similarly sin² sin³ straight line tan² tangent Todh triangle Trinity College Tripos velocity vertex vertical
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