Weekly problem papers, with notes. [With] Solutions1885 |
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Resultat 1-5 av 83
Side 4
... Draw NM parallel to BC , MP parallel to AC . Then MNP is the triangle required . For arc MG = arc GN , .. angle MOG .. angle MPN = = angle GON . angle BAC & c . 6. Let P , Q , R be three points on a parabola whose ordinates are Y1 , 2 ...
... Draw NM parallel to BC , MP parallel to AC . Then MNP is the triangle required . For arc MG = arc GN , .. angle MOG .. angle MPN = = angle GON . angle BAC & c . 6. Let P , Q , R be three points on a parabola whose ordinates are Y1 , 2 ...
Side 7
... of the circles round FDC , BCE . Then the angle FGC = ADC = = CRE . .. EGC + FGC = EGC + EBC = two right angles . .. EG and GF are in one straight line . Bisect EF in L , and draw the tangents FH WEEKLY PROBLEM PAPERS . 7.
... of the circles round FDC , BCE . Then the angle FGC = ADC = = CRE . .. EGC + FGC = EGC + EBC = two right angles . .. EG and GF are in one straight line . Bisect EF in L , and draw the tangents FH WEEKLY PROBLEM PAPERS . 7.
Side 8
John James Milne. Bisect EF in L , and draw the tangents FH , EK , LM to the circle round ABCD . Then and FG.EF = FC.FB = FH2 EG.EF = EC . ED = EK2 .. EF2 = FH2 + EK2 .. 4FL2 + 2R2 = FH2 + R2 + EK2 + · R2 = FO2 + EO2 = 20L2 + 2FL ...
John James Milne. Bisect EF in L , and draw the tangents FH , EK , LM to the circle round ABCD . Then and FG.EF = FC.FB = FH2 EG.EF = EC . ED = EK2 .. EF2 = FH2 + EK2 .. 4FL2 + 2R2 = FH2 + R2 + EK2 + · R2 = FO2 + EO2 = 20L2 + 2FL ...
Side 11
... Draw RM perpendicular to SH . Since CR = CS = CH : . SRH is a right angle . Since CS = CR .. CSR = CRS = RSY ..the triangle SRM = triangle SRY .. SM : - = SY . Similarly it can be shewn that HM = HZ . Since RM2 = SM.MH = SY.HZ = on the ...
... Draw RM perpendicular to SH . Since CR = CS = CH : . SRH is a right angle . Since CS = CR .. CSR = CRS = RSY ..the triangle SRM = triangle SRY .. SM : - = SY . Similarly it can be shewn that HM = HZ . Since RM2 = SM.MH = SY.HZ = on the ...
Side 15
... Draw BG and AF perpendicular to the wall , and CF vertical . Then P , the reaction at B passes through F. Let W be the weight of the rod , and the angle it makes with the horizon , and a its length . Taking moments about A we have AB ...
... Draw BG and AF perpendicular to the wall , and CF vertical . Then P , the reaction at B passes through F. Let W be the weight of the rod , and the angle it makes with the horizon , and a its length . Taking moments about A we have AB ...
Vanlige uttrykk og setninger
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