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Resultat 1-5 av 84
Side 3
... equation , which gives x = ( 2 ) √x2 + a2 + √x2 + b2 = a3 + b3 − c ( a2 + b2 ) c { a2 + b2 - c ( a + b ) } " ( x2 + b2 ) √x2 + b2 .4x2 + 4a2 4x2 + 2 ( a2 - b2 ) + ( 3 ) By subtraction we get ( a2 - b2 ) 2 4.x2 ( a − b ) — 3 * + ( b ...
... equation , which gives x = ( 2 ) √x2 + a2 + √x2 + b2 = a3 + b3 − c ( a2 + b2 ) c { a2 + b2 - c ( a + b ) } " ( x2 + b2 ) √x2 + b2 .4x2 + 4a2 4x2 + 2 ( a2 - b2 ) + ( 3 ) By subtraction we get ( a2 - b2 ) 2 4.x2 ( a − b ) — 3 * + ( b ...
Side 4
John James Milne. = 44 = 1 evidently satisfies the equation , and the product of the roots the last term .. the other root is If x = If x = y , we have r2 = y2 c - a a - by , x2 = = Ꮖ - = У c - a d a + b + c d ( a a ( a2 + b2 + c2 S S ...
John James Milne. = 44 = 1 evidently satisfies the equation , and the product of the roots the last term .. the other root is If x = If x = y , we have r2 = y2 c - a a - by , x2 = = Ꮖ - = У c - a d a + b + c d ( a a ( a2 + b2 + c2 S S ...
Side 12
... equation is 0 , which reduces to ay2 + ( 2acb3 ) y + c2 = 0 . Again , assume y = √x , so that when has any particular value , y the square root of that value . .. x = = y2 , and the required equation is ay + by2 + c = 0 . = = cos 20+ ...
... equation is 0 , which reduces to ay2 + ( 2acb3 ) y + c2 = 0 . Again , assume y = √x , so that when has any particular value , y the square root of that value . .. x = = y2 , and the required equation is ay + by2 + c = 0 . = = cos 20+ ...
Side 13
... equation of any one of - ( x − a cos 0 ) 2 + ( y − - b sin 0 ) 2 = ( x cos a + y sin a − p ) 2 . - If y = 0 , x ... equations are - ( x − a cos 0 ) 2 + ( y − b sin'0 ) 2 = ( x cos 0 + y sin 0 − a ) 2 - - ( it - a cos 0 ) 2 + ( y b ...
... equation of any one of - ( x − a cos 0 ) 2 + ( y − - b sin 0 ) 2 = ( x cos a + y sin a − p ) 2 . - If y = 0 , x ... equations are - ( x − a cos 0 ) 2 + ( y − b sin'0 ) 2 = ( x cos 0 + y sin 0 − a ) 2 - - ( it - a cos 0 ) 2 + ( y b ...
Side 16
... equation has equal 1 b = - = 0 = 1 cd ( a + b ) 1 + d - cd ) + ab ( c + d ) cd ( a + b ) = 0 . roots .. ( ab — cd ) 2 - ( a + b − c − d ) { ab ( c + d ) - - - cd ( a + b ) } 0 . = Now the expression on the left vanishes when a = c , α ...
... equation has equal 1 b = - = 0 = 1 cd ( a + b ) 1 + d - cd ) + ab ( c + d ) cd ( a + b ) = 0 . roots .. ( ab — cd ) 2 - ( a + b − c − d ) { ab ( c + d ) - - - cd ( a + b ) } 0 . = Now the expression on the left vanishes when a = c , α ...
Vanlige uttrykk og setninger
ABCD axis bisects Cambridge centre chord circle College common conic constant coordinates cos² Crown 8vo curve denote described diameter direction directrix distance draw Edition ELEMENTARY ellipse envelope equal equation evidently Fellow focus forces geometrical given gives Illustrations inscribed intersect Join locus Mathematics meet middle point Monday morning moves Multiply normal obtain origin PAPER parabola parallel passes perpendicular plane positive Problems Produce Professor projection Prove question radius respectively resultant right angles roots round School shew sides similar Similarly sin² solution square straight line suppose tangent touches TREATISE triangle Tripos University vertex vertical write
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