Weekly problem papers, with notes. [With] Solutions1885 |
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Side vi
... questions before their notice . For the use of those who do not possess the solutions of these two Triposes , I have added in an Appendix an equal number of alternative questions which are to a great extent similar in character to the ...
... questions before their notice . For the use of those who do not possess the solutions of these two Triposes , I have added in an Appendix an equal number of alternative questions which are to a great extent similar in character to the ...
Side 5
... question . 7. Let ABCD be the square , A resting against the wall and B attached by a string to the point E. BK , CN ' , DH are perpendiculars on the wall . G is the centre of the square , T the tension of the string , W the weight of ...
... question . 7. Let ABCD be the square , A resting against the wall and B attached by a string to the point E. BK , CN ' , DH are perpendiculars on the wall . G is the centre of the square , T the tension of the string , W the weight of ...
Side 10
... question the equality e2 * √ = 1 = should be written € 2πV = 1 = e4 * √ = 1 , e2n = e - 2π = e - 4π e - 2nπ .. raising each to power and this is evidently true when n = 1 . - Similarly it can be shewn that there is a value of each of ...
... question the equality e2 * √ = 1 = should be written € 2πV = 1 = e4 * √ = 1 , e2n = e - 2π = e - 4π e - 2nπ .. raising each to power and this is evidently true when n = 1 . - Similarly it can be shewn that there is a value of each of ...
Side 22
... question may also be solved geometrically as follows : - Let OL , OL ' be the two given straight lines , and let OA bisect the angle between them , so that LOA = L'OA = a . Then if P be any point on 04 , P is the centre of one of the ...
... question may also be solved geometrically as follows : - Let OL , OL ' be the two given straight lines , and let OA bisect the angle between them , so that LOA = L'OA = a . Then if P be any point on 04 , P is the centre of one of the ...
Side 25
... question may be stated thus : If 453.59 kilog . can be carried 1609-27 kilom . for 25.2 francs , how many kilog . can be carried 100 kilom . for 20 francs ? 100 1609-27 :: 453.59 Ans . 25.2 : 20 1609-27 × 453.59 = 5793.24 . 126 729948 ...
... question may be stated thus : If 453.59 kilog . can be carried 1609-27 kilom . for 25.2 francs , how many kilog . can be carried 100 kilom . for 20 francs ? 100 1609-27 :: 453.59 Ans . 25.2 : 20 1609-27 × 453.59 = 5793.24 . 126 729948 ...
Vanlige uttrykk og setninger
a+b+c ABCD axis bisects the angle Cambridge centre chord circle round circle will go circum-circle Clifton College coef College conic const coordinates cos² cosec Crown 8vo denote diameter directrix draw Edition ellipse envelope equal equation Fcap fixed point geometrical given expression hyperbola inscribed circle intersect Join Let ABC Let the tangent locus Mathematics meet middle point Monday afternoon morning nine-point circle nth term orthocentre PAPER parabola parallel perpendicular plane Professor quadrilateral radical axis radius right angles shew shewn sides Similarly sin² sin³ straight line tan² tangent Todh triangle Trinity College Tripos velocity vertex vertical
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