Weekly problem papers, with notes. [With] Solutions1885 |
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Resultat 1-5 av 33
Side 5
... square , A resting against the wall and B attached by a string to the point E. BK , CN ' , DH are perpendiculars on the wall . G is the centre of the square , T the tension of the string , W the weight of the square , R the reaction at ...
... square , A resting against the wall and B attached by a string to the point E. BK , CN ' , DH are perpendiculars on the wall . G is the centre of the square , T the tension of the string , W the weight of the square , R the reaction at ...
Side 12
... square of that value . .. x = , and the required equation is ay + b √y + c = 0 , which reduces to ay2 + ( 2acb2 ) y + c2 = 0 . Again , assume y = √ , so that when has any particular value , the square root of that value ... = y2 , and ...
... square of that value . .. x = , and the required equation is ay + b √y + c = 0 , which reduces to ay2 + ( 2acb2 ) y + c2 = 0 . Again , assume y = √ , so that when has any particular value , the square root of that value ... = y2 , and ...
Side 20
... Square both sides , and clear of fractions ; { k2 + h2 + a2 + 2ah } { ( kx − hy ) 2 + a2 ( y − k ) 2 + 2a ( kx — hy ) ( y − k ) } - = { k2 + h2 + a2 − 2ah } { ( kx · - - 2ah } { ( kx - hy ) 2 + a2 ( y — k ) 2 — 2a ( kx -- hy ) ( y ...
... Square both sides , and clear of fractions ; { k2 + h2 + a2 + 2ah } { ( kx − hy ) 2 + a2 ( y − k ) 2 + 2a ( kx — hy ) ( y − k ) } - = { k2 + h2 + a2 − 2ah } { ( kx · - - 2ah } { ( kx - hy ) 2 + a2 ( y — k ) 2 — 2a ( kx -- hy ) ( y ...
Side 46
... square and add ( 1 ) and ( 2 ) . Similarly , if a2 ..e - 20 = с . : . 0 = 10 log we shall have a cos B a2 C ' = + cos 2B + ... с 2c2 α S ' = sin B + sin 2B + ... C 2c2 C ' = log i = - C C ' = .. the given expression log log = log a NOTE ...
... square and add ( 1 ) and ( 2 ) . Similarly , if a2 ..e - 20 = с . : . 0 = 10 log we shall have a cos B a2 C ' = + cos 2B + ... с 2c2 α S ' = sin B + sin 2B + ... C 2c2 C ' = log i = - C C ' = .. the given expression log log = log a NOTE ...
Side 48
... square on HM is easily seen to be the square required . 6. CAB = 30 ° , DAB = 60 ° 48 SOLUTIONS OF.
... square on HM is easily seen to be the square required . 6. CAB = 30 ° , DAB = 60 ° 48 SOLUTIONS OF.
Vanlige uttrykk og setninger
a+b+c ABCD axis bisects the angle Cambridge centre chord circle round circle will go circum-circle Clifton College coef College conic const coordinates cos² cosec Crown 8vo denote diameter directrix draw Edition ellipse envelope equal equation Fcap fixed point geometrical given expression hyperbola inscribed circle intersect Join Let ABC Let the tangent locus Mathematics meet middle point Monday afternoon morning nine-point circle nth term orthocentre PAPER parabola parallel perpendicular plane Professor quadrilateral radical axis radius right angles shew shewn sides Similarly sin² sin³ straight line tan² tangent Todh triangle Trinity College Tripos velocity vertex vertical
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