Plane Geometry: With Problems and ApplicationsAllyn and Bacon, 1910 - 280 sider |
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Side vi
... half or two thirds , of the applications at the end of each chapter . This would fully cover the college entrance requirements . ( c ) An extended course , including Chapter VII , which con- tains a complete review , together with many ...
... half or two thirds , of the applications at the end of each chapter . This would fully cover the college entrance requirements . ( c ) An extended course , including Chapter VII , which con- tains a complete review , together with many ...
Side 5
... half - line , may be thought of as generated by a point starting from a fixed position and mov- A B ing indefinitely in one direction . The starting point is called the end - point or origin of the ray . If A is the origin of a ray and ...
... half - line , may be thought of as generated by a point starting from a fixed position and mov- A B ing indefinitely in one direction . The starting point is called the end - point or origin of the ray . If A is the origin of a ray and ...
Side 35
... half of the base . 6. Show that an equiangular triangle is equilateral , and conversely . THEOREMS ON PARALLEL LINES . 88. A straight line which cuts two straight lines is called a transversal . The various angles formed are named as ...
... half of the base . 6. Show that an equiangular triangle is equilateral , and conversely . THEOREMS ON PARALLEL LINES . 88. A straight line which cuts two straight lines is called a transversal . The various angles formed are named as ...
Side 46
... half the sum of the sides of the triangle . 3. Show that the segment joining the vertex of an isosceles tri- angle to any point in the base is less than either of the equal sides . 4. Show that any altitude of an equilateral triangle ...
... half the sum of the sides of the triangle . 3. Show that the segment joining the vertex of an isosceles tri- angle to any point in the base is less than either of the equal sides . 4. Show that any altitude of an equilateral triangle ...
Side 60
... half the base . Given a line 7 || AB in △ ABC such that AD DC . = To prove that BE EC and A DE = AB . Proof : Draw EF through E parallel to CA. Now show that AFED is a parallelogram , and that . from which and or ADECA FBE , E B F CE ...
... half the base . Given a line 7 || AB in △ ABC such that AD DC . = To prove that BE EC and A DE = AB . Proof : Draw EF through E parallel to CA. Now show that AFED is a parallelogram , and that . from which and or ADECA FBE , E B F CE ...
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Plane Geometry: With Problems and Applications Herbert Ellsworth Slaught,Nels Johann Lennes Uten tilgangsbegrensning - 1910 |
Plane Geometry: With Problems and Applications Herbert Ellsworth Slaught,Nels Johann Lennes Uten tilgangsbegrensning - 1910 |
Vanlige uttrykk og setninger
ABCD acute angle adjacent angles altitude angle formed angles are equal apothem axes of symmetry axioms base bisects central angle chord circle tangent circumscribed coincide congruent corresponding sides Definition diagonal diameter distance divided dodecagon Draw drawn equal angles equal circles equiangular equilateral triangle EXERCISES exterior angle figure Find the area Find the locus Find the radius fixed point geometric Give the proof given point given segment given triangle Hence hypotenuse hypothesis inches inscribed intersection isosceles trapezoid isosceles triangle length line-segment measure meet middle points number of sides Outline of Proof parallel lines parallelogram perigon perimeter plane proof in full quadrilateral radii ratio rectangle regular hexagon regular octagon regular polygon rhombus right angles right triangle secant semicircle Show shown square straight angle straight line subtend SUGGESTION THEOREM trapezoid triangle ABC vertex vertices width ᎠᏴ
Populære avsnitt
Side 223 - If two triangles have two sides of the one equal to two sides of the other...
Side 41 - An exterior angle of a triangle is equal to the sum of the two opposite interior angles.
Side 121 - Sines that the bisector of an angle of a triangle divides the opposite side into parts proportional to the adjacent sides.
Side 60 - The straight line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of it 46 INTERCEPTS BY PARALLEL LINES.
Side 182 - The areas of two regular polygons of the same number of sides are to each other as the squares of their radii, or as the squares of their apothems.
Side 161 - The formula states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the base and altitude.
Side 227 - Find the locus of a point such that the difference of the squares of its distances from two fixed points is a constant.
Side 210 - The area of a rectangle is equal to the product of its base and altitude.
Side 31 - Kuclid divided unproved propositions into two classes: axioms, or "common notions," which are true of all things, such as, " If things are equal to the same thing they are equal to each other"; and postulates, which apply only to geometry, such as,