Plane Geometry: With Problems and ApplicationsAllyn and Bacon, 1910 - 280 sider |
Inni boken
Resultat 1-5 av 28
Side 11
... hypotenuse in dis- Hypotenuse tinction from the other two sides , which are sometimes called its legs . 24. The side of a triangle on which it is supposed to stand is called its base . called the vertex angle , and its vertex is the ...
... hypotenuse in dis- Hypotenuse tinction from the other two sides , which are sometimes called its legs . 24. The side of a triangle on which it is supposed to stand is called its base . called the vertex angle , and its vertex is the ...
Side 35
... hypotenuse of a right triangle is greater than either leg . 2. Show that not more than two equal line - segments can be drawn from a point to a straight line . SUGGESTION . Suppose a third drawn . Then apply §§ 37 , 83 , 84 . 3. Show by ...
... hypotenuse of a right triangle is greater than either leg . 2. Show that not more than two equal line - segments can be drawn from a point to a straight line . SUGGESTION . Suppose a third drawn . Then apply §§ 37 , 83 , 84 . 3. Show by ...
Side 41
... hypotenuse and an acute angle of one are equal respectively to the hypotenuse and an acute angle of the other , the triangles are congruent . Prove in full . 8. Can a triangle have two right angles ? Two obtuse angles ? Can the sum of ...
... hypotenuse and an acute angle of one are equal respectively to the hypotenuse and an acute angle of the other , the triangles are congruent . Prove in full . 8. Can a triangle have two right angles ? Two obtuse angles ? Can the sum of ...
Side 43
... hypotenuse and one side of the other , the triangles are congruent . B B 444 A CA C'A Given the right △ ABC and A'B'C ' , having AB = A'B ' and BC = B'C ' . To prove that △ ABCAA'B'C ' . Proof : Place the triangles so that BC and B'C ...
... hypotenuse and one side of the other , the triangles are congruent . B B 444 A CA C'A Given the right △ ABC and A'B'C ' , having AB = A'B ' and BC = B'C ' . To prove that △ ABCAA'B'C ' . Proof : Place the triangles so that BC and B'C ...
Side 65
... hypotenuse is twice as long as one side , then one acute angle is 60 ° and the other 30 ° . SUGGESTION . Let D be the middle point of AB . Use Ex . 12 and the hypothesis to show that △ ACD is equilateral . D A E Prove the converse by ...
... hypotenuse is twice as long as one side , then one acute angle is 60 ° and the other 30 ° . SUGGESTION . Let D be the middle point of AB . Use Ex . 12 and the hypothesis to show that △ ACD is equilateral . D A E Prove the converse by ...
Andre utgaver - Vis alle
Plane Geometry: With Problems and Applications Herbert Ellsworth Slaught,Nels Johann Lennes Uten tilgangsbegrensning - 1910 |
Plane Geometry: With Problems and Applications Herbert Ellsworth Slaught,Nels Johann Lennes Uten tilgangsbegrensning - 1910 |
Vanlige uttrykk og setninger
ABCD acute angle adjacent angles altitude angle formed angles are equal apothem axes of symmetry axioms base bisects central angle chord circle tangent circumscribed coincide congruent corresponding sides Definition diagonal diameter distance divided dodecagon Draw drawn equal angles equal circles equiangular equilateral triangle EXERCISES exterior angle figure Find the area Find the locus Find the radius fixed point geometric Give the proof given point given segment given triangle Hence hypotenuse hypothesis inches inscribed intersection isosceles trapezoid isosceles triangle length line-segment measure meet middle points number of sides Outline of Proof parallel lines parallelogram perigon perimeter plane proof in full quadrilateral radii ratio rectangle regular hexagon regular octagon regular polygon rhombus right angles right triangle secant semicircle Show shown square straight angle straight line subtend SUGGESTION THEOREM trapezoid triangle ABC vertex vertices width ᎠᏴ
Populære avsnitt
Side 223 - If two triangles have two sides of the one equal to two sides of the other...
Side 41 - An exterior angle of a triangle is equal to the sum of the two opposite interior angles.
Side 121 - Sines that the bisector of an angle of a triangle divides the opposite side into parts proportional to the adjacent sides.
Side 60 - The straight line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of it 46 INTERCEPTS BY PARALLEL LINES.
Side 182 - The areas of two regular polygons of the same number of sides are to each other as the squares of their radii, or as the squares of their apothems.
Side 161 - The formula states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the base and altitude.
Side 227 - Find the locus of a point such that the difference of the squares of its distances from two fixed points is a constant.
Side 210 - The area of a rectangle is equal to the product of its base and altitude.
Side 31 - Kuclid divided unproved propositions into two classes: axioms, or "common notions," which are true of all things, such as, " If things are equal to the same thing they are equal to each other"; and postulates, which apply only to geometry, such as,