Elements of Geometry: With Practical Applications ...H.H. Howley and Company, 1847 - 308 sider |
Inni boken
Resultat 1-5 av 15
Side 176
... MN the plane of the lines . Through P , draw in the plane MN any line as PQ ; and through any M B C point of this line , as Q , draw BQC , so that BQ = QC ( B. IV , Prop . vI ) : join AB , AQ , AC . The base BC being divided into two ...
... MN the plane of the lines . Through P , draw in the plane MN any line as PQ ; and through any M B C point of this line , as Q , draw BQC , so that BQ = QC ( B. IV , Prop . vI ) : join AB , AQ , AC . The base BC being divided into two ...
Side 177
... plane MN . Cor . 2. At a given point P on a plane , it is impossible to erect more than one perpendicular to that plane . For , if there could be two perpendiculars at the same point P , draw along these two perpendiculars a plane ...
... plane MN . Cor . 2. At a given point P on a plane , it is impossible to erect more than one perpendicular to that plane . For , if there could be two perpendiculars at the same point P , draw along these two perpendiculars a plane ...
Side 178
... plane , are equal ; and , of two oblique lines unequally distant from the ... plane , the point P at which the perpendicular drawn from A would meet that ... MN ; which inclination is equal with respect to all such lines AB , AC , AD ...
... plane , are equal ; and , of two oblique lines unequally distant from the ... plane , the point P at which the perpendicular drawn from A would meet that ... MN ; which inclination is equal with respect to all such lines AB , AC , AD ...
Side 179
... plane . Let AP be a line perpendicular to the plane MN , and PD perpen- dicular to BC ; then will AD be perpendicular to BC . Take DB DC , and join PB , = PC , AB , AC . Since DB = DC , the - = D E M two right - angled triangles PDB ...
... plane . Let AP be a line perpendicular to the plane MN , and PD perpen- dicular to BC ; then will AD be perpendicular to BC . Take DB DC , and join PB , = PC , AB , AC . Since DB = DC , the - = D E M two right - angled triangles PDB ...
Side 180
... plane , are conceived as forming a right angle with each other , because AD and the line drawn through one of its ... MN ; then will ED be also perpendicular to this plane . N P M Along the parallels AP , DE , ex- tend a plane ; its ...
... plane , are conceived as forming a right angle with each other , because AD and the line drawn through one of its ... MN ; then will ED be also perpendicular to this plane . N P M Along the parallels AP , DE , ex- tend a plane ; its ...
Andre utgaver - Vis alle
Elements of Geometry: With, Practical Applications George Roberts Perkins Uten tilgangsbegrensning - 1850 |
Elements of Geometry: With Practical Applications Designed for Beginners George Roberts Perkins Uten tilgangsbegrensning - 1853 |
Elements of Geometry With Practical Applications George R Perkins Ingen forhåndsvisning tilgjengelig - 2023 |
Vanlige uttrykk og setninger
a+b+c AC² altitude angle ACD angle BAC bisect centre chord circ circular sector circumference cone consequently convex surface cylinder diagonal diameter distance draw equal and parallel equiangular equilateral triangle equivalent exterior angle figure formed four right angles given line greater half the arc hypothenuse inscribed circle intersection isosceles join less Let ABC lines drawn magnitude measured by half meet multiplied number of sides opposite angles parallel planes parallelogram parallelopipedon pendicular perimeter perpendicular plane MN point G prism PROBLEM produced Prop PROPOSITION pyramid radii radius rectangle regular polygon respectively equal right angles right-angled triangle Sabc Schol Scholium semicircle semicircumference side AC similar similar triangles solid angle solid described sphere spherical triangle square straight line suppose tangent THEOREM three sides triangle ABC triangular prism vertex VIII
Populære avsnitt
Side 37 - The sum of all the angles of a polygon is equal to twice as many right angles as the polygon has sides, less two.
Side 180 - THEOREM. If one of two parallel lines is perpendicular to a plane, the other will also be perpendicular to this plane. Let AP & ED be parallel lines, of which AP is perpendicular to the plane MN ; then will ED be also perpendicular to this plane.
Side 139 - PROBLEM. To inscribe a circle in a given triangle. Let ABC be the given triangle : it is required to inscribe a circle in the triangle ABC.
Side 224 - The radius of a sphere is a straight line, drawn from the centre to any point of the...
Side 43 - In a right-angled triangle, the side opposite the right angle is" called the Hypothenuse ; and the other two sides are cal4ed the Legs, and sometimes the Base and Perpendicular.
Side 184 - THEOREM. If two angles, not situated in the same plane, have their sides parallel and lying in the same direction, they will be equal, and the planes in which they are situated will be parallel.
Side 10 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Side 226 - We conclude then, that the solidity of a cylinder is equal to the product of its base by its altitude.
Side 22 - If two sides and the included angle of the one are respectively equal to two sides and the included angle of the other...
Side 12 - If equals be added to unequals, the wholes are unequal. V. If equals be taken from unequals, the remainders are unequal. VI. Things which are double of the same, are equal to one another.