An introduction to geometry, consisting of Euclid's Elements, book i, accompanied by numerous explanations, questions, and exercises, by J. Walmsley. [With] Answers, Volum 11884 |
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Resultat 1-5 av 26
Side
... Exterior Angles of Rectilineal Figures ... ... ... ... SECTION VIII . , PROPS . 33 , 34. — Parts of a Parallelogram ... SECTION IX . , PROPS . 35-42 . - Parallelism in relation to Equivalent Parallelograms and Triangles SECTION X ...
... Exterior Angles of Rectilineal Figures ... ... ... ... SECTION VIII . , PROPS . 33 , 34. — Parts of a Parallelogram ... SECTION IX . , PROPS . 35-42 . - Parallelism in relation to Equivalent Parallelograms and Triangles SECTION X ...
Side ii
... Exterior Angles of Rectilineal Figures ... ... ... SECTION VIII . , PROPS . 33 , 34. — Parts of a Parallelogram ... SECTION IX . , PROPS . 35-42 . - Parallelism in relation to Equivalent Parallelograms and Triangles SECTION X. , PROPS ...
... Exterior Angles of Rectilineal Figures ... ... ... SECTION VIII . , PROPS . 33 , 34. — Parts of a Parallelogram ... SECTION IX . , PROPS . 35-42 . - Parallelism in relation to Equivalent Parallelograms and Triangles SECTION X. , PROPS ...
Side 57
... EXTERIOR ANGLES OF TRIANGLES . G B H In the accompanying diagram , the sides of the triangle ABC will be found to be each produced both ways . The number of the angles at the points A , B , and C'is thereby increased fourfold . The ...
... EXTERIOR ANGLES OF TRIANGLES . G B H In the accompanying diagram , the sides of the triangle ABC will be found to be each produced both ways . The number of the angles at the points A , B , and C'is thereby increased fourfold . The ...
Side 58
... exterior angle is greater than either of the interior opposite angles . Let ABC be a triangle whose side BC is produced to D. Then the exterior angle ACD shall be greater than either of the interior opposite angles CBA or BAC . Bisect ...
... exterior angle is greater than either of the interior opposite angles . Let ABC be a triangle whose side BC is produced to D. Then the exterior angle ACD shall be greater than either of the interior opposite angles CBA or BAC . Bisect ...
Side 59
... exterior angle of the triangle ABC , and ABC is an interior angle opposite to it ; therefore the angle ACD is greater than ABC . To each of these unequals add the angle ACB ; ( I. 16 ) therefore the angles ACD , ACB are greater than ABC ...
... exterior angle of the triangle ABC , and ABC is an interior angle opposite to it ; therefore the angle ACD is greater than ABC . To each of these unequals add the angle ACB ; ( I. 16 ) therefore the angles ACD , ACB are greater than ABC ...
Andre utgaver - Vis alle
An Introduction to Geometry, Consisting of Euclid's Elements, Book I ... Euclides Ingen forhåndsvisning tilgjengelig - 2013 |
An Introduction to Geometry, Consisting of Euclid's Elements, Book I ... Euclides Ingen forhåndsvisning tilgjengelig - 2023 |
An Introduction to Geometry, Consisting of Euclid's Elements, Book I ... Euclides Ingen forhåndsvisning tilgjengelig - 2018 |
Vanlige uttrykk og setninger
AB is equal AC is equal adjacent angles alternate angle angle ABC angle ACB angle AGH angle BAC angle BCD angle equal angles CBA axiom base BC bisects the angle centre circle circumference Constr construction definition describe diagonal Diagram diameter enunciation equal and parallel equal angles equal sides equal to BC EQUIANGULAR POLYGONS equilateral triangle Euclid Euclid's Elements exterior four right angles Geometry given angle given point given straight line greater hypotenuse hypothesis inference isosceles triangle join less Let ABC magnitude meet middle point opposite angles opposite interior angle opposite sides pair of equal parallel to BC parallelogram perpendicular Postulate produced proof Prop proposition prove quadrilateral rectilineal figure respectively equal rhombus right angles right-angled triangle sides equal square supplementary angles theorems thesis trapezium triangle ABC triangles are equal unequal vertex Wherefore
Populære avsnitt
Side 132 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Side 86 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 139 - If two triangles have two angles of the one equal to two angles of the other, each to each, and also one side of the one equal to the corresponding side of the other, the triangles are congruent.
Side 133 - The complements of the parallelograms, which are about the diameter of any parallelogram, are equal to one another.
Side 134 - Prove that parallelograms on the same base and between the same parallels are equal in area.
Side 134 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line ; it is required to draw a straight line through the point A, parallel to the straight hue BC.
Side 50 - if two straight lines" &c. QED COR. 1. From this it is manifest, that if two straight lines cut one another, the angles which they make at the point where they cut, are together equal to four right angles.
Side 20 - PROB. from a given point to draw a straight line equal to a given straight line. Let A be the given point, and BC the given straight line : it is required to draw from the point A a straight line equal to BC.
Side 96 - Parallelograms upon the same base and between the same parallels, are equal to one another.
Side 49 - If at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles ; then these two straight lines shall be in one and the same straight line.