## A Compendious System of Practical Surveying, and Dividing of Land: Concisely Defined, Methodically Arranged, and Fully Exemplified : the Whole Adapted for the Easy and Regular Instruction of Youth, in Our American Schools |

### Inni boken

Side 112

As radius 90° 10.00000 AB 16 1.20412 Is to the si { S to sides AC 10.12 1.00518

So is sine of the angle 30° 9.69897 11.90827 10.00000 To

1.90827 A. 4,048 4. ,192 40 P. 7,680 Area 4A. 0R 7P. A. ~ | B * JVote. The area ...

As radius 90° 10.00000 AB 16 1.20412 Is to the si { S to sides AC 10.12 1.00518

So is sine of the angle 30° 9.69897 11.90827 10.00000 To

**double area**;)80.961.90827 A. 4,048 4. ,192 40 P. 7,680 Area 4A. 0R 7P. A. ~ | B * JVote. The area ...

Side 138

... and that the sum of the north

BGIh, and hUTP; therefore the sum of the north

leaves the

... and that the sum of the north

**areas**is equal to the sum of the parallelogramsBGIh, and hUTP; therefore the sum of the north

**areas**taken from that of the south,leaves the

**area**of the parallelogram DBPF, which is**double**the**area**of the map. Side 207

To find the area of IAGI. - As radius 90° 10.00000 Is to IA 29.47 1.46938 #3 18.27

1.2617& So is sine [I. 31.30 9.7.1809 ** 12.44921 40.00000 To

281.33 2.44,921 To find the area of IGFI. As radius 90 10.00000 Is to IG 18.27 ...

To find the area of IAGI. - As radius 90° 10.00000 Is to IA 29.47 1.46938 #3 18.27

1.2617& So is sine [I. 31.30 9.7.1809 ** 12.44921 40.00000 To

**double area**281.33 2.44,921 To find the area of IGFI. As radius 90 10.00000 Is to IG 18.27 ...

Side 208

To find the area of LABI. As radius 90 10.00000 Is to LAY 29.47 1.46938 IB 35.43

1,54937 So is sine [I 13.45 9,37600 12.39473 10.00000 To

2.394.75 z To find the area of IBCI. As radius 90 10,00000 Is to IB 35.43 ...

To find the area of LABI. As radius 90 10.00000 Is to LAY 29.47 1.46938 IB 35.43

1,54937 So is sine [I 13.45 9,37600 12.39473 10.00000 To

**double area**248.172.394.75 z To find the area of IBCI. As radius 90 10,00000 Is to IB 35.43 ...

Side 209

To find the area of IDEI. As radius 90 * . 10.00000 Is to ID 30.75 1.487.84 IE s

22.23 1.34694 So is sine [I 26.30 9.64953 12.48431 10.00000 To

305 2.48431 *

To find the area of IDEI. As radius 90 * . 10.00000 Is to ID 30.75 1.487.84 IE s

22.23 1.34694 So is sine [I 26.30 9.64953 12.48431 10.00000 To

**double area**305 2.48431 *

**Double area**. IAGI 281.33 IGFI so Add IFEI 123.51 IAGFEI 463.10 ...### Hva folk mener - Skriv en omtale

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### Andre utgaver - Vis alle

A Compendious System of Practical Surveying, and Dividing of Land: Concisely ... T. Hamilton,S. Hilles Uten tilgangsbegrensning - 1814 |

A Compendious System of Practical Surveying, and Dividing of Land: Concisely ... Zachariah Jess,Evans 35670 Ingen forhåndsvisning tilgjengelig - 2016 |

### Vanlige uttrykk og setninger

40 perches acres angle opposite base BC bearing and distance centre chains chord of 60 circle Co-sec Co-sine Co-tang column compasses Dep Lat describe an arch diameter diff difference of latitude Dist divided division line double area East ExAMPLE extent will reach feet find the angles find the area find the bearing find the Content find the difference find the hypothenuse find the logarithm foot GEOMETRICAL hypothenuse 121 intersect JVote Lat Dep latitude and departure left hand line of numbers line of sines meridian distances Multiply North Oblique Angled Trigonometry opposite angle parallelogram perpen perpendicular BC piece of ground PROBLEM radius 90 Rhombus right angled triangle Right Angled Trigonometry RULE scale of equal Secant side BC South square perches square root subtracted sun’s Tang tangent Trapezium TRAVERSE TABLE West

### Populære avsnitt

Side 50 - ЙО, 30, &c., to the left hand, where it ends at 87 degrees. This line. with the line of equal parts, marked (EP), under it, are used together, and only in Mercator's Sailing. The upper line contains the degrees of the meridian, or latitude in a Mercator's chart, corresponding to the degrees of longitude on the lower line. The use of this Scale in solving the usual problems of Trigonometry...

Side 80 - To the length of the given side ; So is the sine of the angle opposite the required side. To the length of the required side.

Side 4 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, etc.

Side 44 - I tenth part ; and the next 2, 2 tenth parts; and 10 at the end will be but one whole number or integer. As the figures are increased or diminished in their value, so in like manner must all the intermediate strokes or subdivisions be increased or diminished ; that is, if the first...

Side 47 - EXAMPLE. If the diameter of a circle be 7 inches, and the circumference 22, what is the circumference of another circle, the diameter of which is 14 inches ? Extend from 7 to 22, that extent will reach from 14 to 44 the same way.

Side 217 - Then if the true and magnetic amplitudes be both north or both south their difference is the variation, but if one be north and the other south their sum is the variation ; and to know whether it be easterly or westerly, suppose the observer looking towards that point of the compass representing the magnetic amplitude; then if the true amplitude be to the...

Side 220 - Ъои) on the east, or both on the west side of the meridian, their difference is the variation : but if one be on the east, and the other on the west side of the meridian, their sum is the variation ; and to know if it be east or west, suppose the observer looking towards that point of the compass representing the magnetic azimuth ; then if the true •azimuth be to the right of the magnetic, the variation is east, but if the true be to the left of the magnetic, the variation is west. EXAMPLE....

Side 215 - As the length of the whole line, Is to 57.3 Degrees,* So is the said distance, To the difference of Variation required. EXAMPLE. Suppose it be required to run a line which some years ago bore N.

Side 219 - . 2. Subtract the Sun's declination from 90«, when the latitude and declination are of the same name, or add it to 90*, when they are of contrary names ; and the sum, or remainder, will be the Sun's polar distance. , 3. Add together the Sun's polar distance, the latitude of the place, and the altitude of the Sun; take the difference between half their sum and the polar distance, and note the remainder.

Side 49 - ... degrees of the quadrant, begins at the right hand against 90° on the sines, and from thence is numbered towards the left hand thus : 10, 20...