Solid and Spherical Geometry and Conic Sections: Being a Treatise on the Higher Branches of Synthetical Geometry, Containing the Solid and Spherical Geometry of Playfair ...William and Robert Chambers and sold by all booksellers, 1837 - 164 sider |
Inni boken
Resultat 1-5 av 22
Side 19
... ABCD be cut by the plane EV , which is parallel to the opposite planes AR , HD , and divides the whole into the solids ABFV , EGCD ; as the base AEFY to the base EHCF , so is the solid ABFV to the solid EGCD . Produce AH both ways , and ...
... ABCD be cut by the plane EV , which is parallel to the opposite planes AR , HD , and divides the whole into the solids ABFV , EGCD ; as the base AEFY to the base EHCF , so is the solid ABFV to the solid EGCD . Produce AH both ways , and ...
Side 32
... ABCD and EFGH be two pyramids , having equal bases BDC and FGH , and equal altitudes , namely , the per- pendiculars AQ and ES drawn from A and E upon the planes BDC and FGH ; and let them be cut by planes parallel to BDC and FGH , and ...
... ABCD and EFGH be two pyramids , having equal bases BDC and FGH , and equal altitudes , namely , the per- pendiculars AQ and ES drawn from A and E upon the planes BDC and FGH ; and let them be cut by planes parallel to BDC and FGH , and ...
Side 33
... ABCD be a pyramid , and Z * a given solid ; a series of prisms having all the same altitude , may be circumscribed * The solid Z is not represented in the figure of this or the following proposition . about the pyramid ABCD , so that ...
... ABCD be a pyramid , and Z * a given solid ; a series of prisms having all the same altitude , may be circumscribed * The solid Z is not represented in the figure of this or the following proposition . about the pyramid ABCD , so that ...
Side 34
... ABCD , so that their sum shall exceed ABCD by a solid less than Z .. K B I N W C V H M F Let Z be equal to a prism standing on the same base with the pyramid , namely , the triangle BCD , and having for its altitude the perpendicular ...
... ABCD , so that their sum shall exceed ABCD by a solid less than Z .. K B I N W C V H M F Let Z be equal to a prism standing on the same base with the pyramid , namely , the triangle BCD , and having for its altitude the perpendicular ...
Side 35
... ABCD , because ABCD is greater than the sum of the inscribed prisms . Much more , therefore , is the excess of the circumscribed prisms above the pyramid , less than the solid Z. A series of prisms of the same altitude has therefore ...
... ABCD , because ABCD is greater than the sum of the inscribed prisms . Much more , therefore , is the excess of the circumscribed prisms above the pyramid , less than the solid Z. A series of prisms of the same altitude has therefore ...
Andre utgaver - Vis alle
Solid and Spherical Geometry and Conic Sections: Being a Treatise on the ... A. Bell Uten tilgangsbegrensning - 1837 |
Solid and Spherical Geometry and Conic Sections: Being a Treatise on the ... William Chambers,Robert Chambers,A Bell Ingen forhåndsvisning tilgjengelig - 2018 |
Solid and Spherical Geometry and Conic Sections: Being a Treatise on the ... William Chambers,Robert Chambers,A Bell Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
absciss altitude angle ABC assymptotes base centre CG² circumference common section cone Conic Sections conic surface conjugate axis conjugate diameters cord cosine cotangent dicular directrix distance draw EK KF ellipse equal Pl foci focus given angle given point greater Hence hyperbola hypotenuse inclination intercepted intersection Let ABC line be drawn line of common ordinate parabola parallel planes parallelogram pendicular perpen perpendicular perspective plane passing point of contact pole primitive prism projection pyramid ABCD quadrant radius ratio rectangle right angles right-angled spherical triangles segments semi-ordinate semicircle sides similar triangles sine small circle solid angle solid KQ solid less solid parallelopipeds sphere spherical angle spherical triangle square subcontrary surface tangent THEOREM transverse axis vertex vertical wherefore
Populære avsnitt
Side 52 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 17 - A cone is a solid figure described by the revolution of a right-angled triangle about one of the sides containing the right angle, which side remains fixed.
Side 27 - LR, the base of which is the parallelogram LQ, and of which LM is one of its insisting straight lines : therefore, because the parallelogram AB is equal to CD, as the base AB is to the base LQ, so is (7.
Side 19 - DAB, which contain the solid angle at A, are less than four right angles. Next, let the solid angle at A be contained by any number of plane angles BAC, CAD, DAE, EAF, FAB. These shall together be less than four right angles.
Side 29 - FC, as the solid HD to the solid DC. But the base HF is equal to the base AE, and the solid GK to the solid AB ; therefore, as the base AE to the base CF, so is the solid AB to the solid CD.
Side 55 - EM (2.) are ^quadrants, and FL, EM together, that is, FE and ML together, are equal to a semicircle. But since A is the pole of ML, ML is the measure of the angle BAC (3.), consequently FE is the supplement of the measure of the angle BAC.
Side 21 - And AB is parallel to CD ; therefore AC is a parallelogram. In like manner, it may be proved, that each of the figures CE, FG, GB, BF, AE is a parallelogram: Join AH, DF; and...
Side 7 - If two straight lines be at right angles to the same plane, they shall be parallel to one another. Let the straight lines AB, CD be at right angles to the same plane.
Side 11 - CA is at right angles to the given plane, it makes right angles with every straight line meeting it in that plane. But DAE, which is in that plane, meets CA : therefore CAE is a right angle. For the same reason BAE is a right angle. Wherefore the angle CAE is equal to the angle BAE ; and they are in one plane, which is impossible. Also, from a point above a plane, there can be but one perpendicular to that plane ; for if there could be two, they would be parallel (6.
Side 3 - The inclination of a straight line to a plane is the acute angle contained by that straight line, and another drawn from the point in which the first line meets the plane, to the point in which...