## Solid and Spherical Geometry and Conic Sections: Being a Treatise on the Higher Branches of Synthetical Geometry, Containing the Solid and Spherical Geometry of Playfair ... |

### Inni boken

Resultat 1-5 av 17

Side 19

If a solid parallelopiped be cut by a plane parallel to two of its opposite planes , it

will be

the solid parallelopiped ABCD be cut by the plane EV , which is parallel to the ...

If a solid parallelopiped be cut by a plane parallel to two of its opposite planes , it

will be

**divided**into two solids , which will be to one another as their bases . Letthe solid parallelopiped ABCD be cut by the plane EV , which is parallel to the ...

Side 21

and through these points let planes LS , MT , & c . pass , parallel to AE , then AG

will be

**Divide**AH ! L into 4 and HB into M N H Ö ' B 3 equal parts in L , M , N , O , and P ,and through these points let planes LS , MT , & c . pass , parallel to AE , then AG

will be

**divided**into 4 , and HF into 3 , equal parallelopipeds , AS , LT , & c . Side 35

, HT , TU , UV , VE , and through the points T , U , and V , let the sections TZW ,

UEX , VOY , be made parallel to the base FGH . The section NQL is equal to the ...

**Divide**EH into the same number of equal parts into which AD is**divided**, namely, HT , TU , UV , VE , and through the points T , U , and V , let the sections TZW ,

UEX , VOY , be made parallel to the base FGH . The section NQL is equal to the ...

Side 36

The prism ABCDEF may be

bases . Join AE , EC , CD ; and because ABED is a parallelogram , of which AE is

the diameter , the tri - F angle ADE is equal ( Pl . Ge . I . 34 ) to the triangle ABE ...

The prism ABCDEF may be

**divided**into three equal pyramids having triangularbases . Join AE , EC , CD ; and because ABED is a parallelogram , of which AE is

the diameter , the tri - F angle ADE is equal ( Pl . Ge . I . 34 ) to the triangle ABE ...

Side 37

But the pyramids ADEC , ABEC , DFEC , make up the whole prism ABCDEF ;

therefore the prism ABCDEF is

From this it is manifest that every pyramid is the third part of a prism which has the

same ...

But the pyramids ADEC , ABEC , DFEC , make up the whole prism ABCDEF ;

therefore the prism ABCDEF is

**divided**into three equal pyramids . Cor . 1 . –From this it is manifest that every pyramid is the third part of a prism which has the

same ...

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### Andre utgaver - Vis alle

Solid and Spherical Geometry and Conic Sections: Being a Treatise on the ... A. Bell Uten tilgangsbegrensning - 1837 |

Solid and Spherical Geometry and Conic Sections: Being a Treatise on the ... William Chambers,Robert Chambers,A Bell Ingen forhåndsvisning tilgjengelig - 2018 |

Solid and Spherical Geometry and Conic Sections: Being a Treatise on the ... William Chambers,Robert Chambers,A Bell Ingen forhåndsvisning tilgjengelig - 2015 |

### Vanlige uttrykk og setninger

ABCD affection altitude angle ABC axis base bisects called centre circle common section cone conjugate consequently contained cord cosine curve cylinder described diameter difference distance divided draw drawn ellipse equal extremities fall figure foci focus fore given given point greater half Hence hyperbola inclination intercepted intersection join less line be drawn lines drawn manner measure meet namely opposite ordinate parabola parallel parallelogram pass perpendicular perspective plane point of contact pole primitive prism produced projection proportional PROPOSITION proved pyramid quadrant radius ratio reason rectangle right angles segments semi-ordinate sides similar sine small circle solid sphere spherical triangle square straight line surface tangent THEOREM third transverse triangle vertex vertical

### Populære avsnitt

Side 50 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.

Side 15 - A cone is a solid figure described by the revolution of a right-angled triangle about one of the sides containing the right angle, which side remains fixed.

Side 25 - LR, the base of which is the parallelogram LQ, and of which LM is one of its insisting straight lines : therefore, because the parallelogram AB is equal to CD, as the base AB is to the base LQ, so is (7.

Side 17 - DAB, which contain the solid angle at A, are less than four right angles. Next, let the solid angle at A be contained by any number of plane angles BAC, CAD, DAE, EAF, FAB. These shall together be less than four right angles.

Side 27 - FC, as the solid HD to the solid DC. But the base HF is equal to the base AE, and the solid GK to the solid AB ; therefore, as the base AE to the base CF, so is the solid AB to the solid CD.

Side 53 - EM (2.) are ^quadrants, and FL, EM together, that is, FE and ML together, are equal to a semicircle. But since A is the pole of ML, ML is the measure of the angle BAC (3.), consequently FE is the supplement of the measure of the angle BAC.

Side 19 - And AB is parallel to CD ; therefore AC is a parallelogram. In like manner, it may be proved, that each of the figures CE, FG, GB, BF, AE is a parallelogram: Join AH, DF; and...

Side 5 - If two straight lines be at right angles to the same plane, they shall be parallel to one another. Let the straight lines AB, CD be at right angles to the same plane.

Side 9 - CA is at right angles to the given plane, it makes right angles with every straight line meeting it in that plane. But DAE, which is in that plane, meets CA : therefore CAE is a right angle. For the same reason BAE is a right angle. Wherefore the angle CAE is equal to the angle BAE ; and they are in one plane, which is impossible. Also, from a point above a plane, there can be but one perpendicular to that plane ; for if there could be two, they would be parallel (6.

Side 1 - The inclination of a straight line to a plane is the acute angle contained by that straight line, and another drawn from the point in which the first line meets the plane, to the point in which...