A School Geometry, Deler 1-4Macmillan and Company, 1908 |
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Resultat 1-5 av 38
Side 3
... Suppose that the arm OA is fixed , and that OB turns about the point ( as shewn by the arrow ) . Suppose also that OB began its turning from the position OA . Then the size of the angle AOB is measured by the amount of turning required ...
... Suppose that the arm OA is fixed , and that OB turns about the point ( as shewn by the arrow ) . Suppose also that OB began its turning from the position OA . Then the size of the angle AOB is measured by the amount of turning required ...
Side 6
... suppose ( i ) A straight line to be drawn perpendicular to a given straight line from any point in it . ( ii ) A finite straight line to be bisected at a point . ( iii ) An angle to be bisected by a line . SUPERPOSITION AND EQUALITY ...
... suppose ( i ) A straight line to be drawn perpendicular to a given straight line from any point in it . ( ii ) A finite straight line to be bisected at a point . ( iii ) An angle to be bisected by a line . SUPERPOSITION AND EQUALITY ...
Side 10
... Suppose OD is at right angles to BA , Proof . Then the AOC , COB together = the three AOC , COD , DOB . Also the AOD , DOB together == - the three = AOC , COD , DOB . ... the AOC , COB together the " AOD , DOB = two right angles ...
... Suppose OD is at right angles to BA , Proof . Then the AOC , COB together = the three AOC , COD , DOB . Also the AOD , DOB together == - the three = AOC , COD , DOB . ... the AOC , COB together the " AOD , DOB = two right angles ...
Side 14
... Suppose the line COD to revolve about O until OC turns into the position OA . Then at the same moment OD must reach the position OB ( for AOB and COD are straight ) . Thus the same amount of turning is required to close the LAOC as to ...
... Suppose the line COD to revolve about O until OC turns into the position OA . Then at the same moment OD must reach the position OB ( for AOB and COD are straight ) . Thus the same amount of turning is required to close the LAOC as to ...
Side 20
... Suppose that AD is the line which bisects the BAC , and let it meet BC in D. 1st Proof . because Then in the △ BAD , CAD , BA = CA , AD is common to both triangles , and the included BAD = the included CAD ; .. the triangles are equal ...
... Suppose that AD is the line which bisects the BAC , and let it meet BC in D. 1st Proof . because Then in the △ BAD , CAD , BA = CA , AD is common to both triangles , and the included BAD = the included CAD ; .. the triangles are equal ...
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Vanlige uttrykk og setninger
AB² adjacent angles altitude angle equal base BC bisector bisects circle of radius circle whose centre circles which touch circum-circle circumference circumscribed coincide common tangents concyclic Construct a triangle diagonals diagram diameter distance divided draw a circle equal in area equidistant escribed circles Euclid exterior angles Find the area find the locus given angle given circle given point given straight line given triangle greater Hence hypotenuse inches inscribed isosceles triangle length Let ABC meet metres middle point millimetre nine-points circle opposite sides orthocentre par¹ parallelogram pedal triangle perp PROBLEM produced Proof radii rect rectangle rectangle contained rectilineal figure required to prove respectively rhombus right angles right-angled triangle segment shew shewn straight line drawn tangent Theor Theorem trapezium triangle ABC triangles are equal vertex vertical angle
Populære avsnitt
Side xi - IF two triangles have two angles of one equal to two angles of the other, each to each ; and one side equal to one side, viz. either the sides adjacent to the equal...
Side 44 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 190 - Upon a given straight line to describe a segment of a circle, which shall contain an angle equal to a given rectilineal angle.
Side 12 - If, at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles, these two straight lines shall be in one and the same straight line.
Side 5 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Side 122 - The square described on the hypothenuse of a rightangled triangle is equal to the sum of the squares described on the other two sides.
Side 28 - If one side of a triangle be produced, the exterior angle is greater than either of the interior opposite angles.
Side x - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Side 65 - The sum of the perpendiculars from any point within an equilateral triangle to the three sides is equal to the altitude of the triangle (Fig.