Class lessons on Euclid1882 |
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Side 13
... double of the same thing are equal to one another . ' 7. ' Things which are halves of the same thing are equal to one another . ' These axioms may of course be extended to any multiple or fraction . Axioms 2-5 form a second connected ...
... double of the same thing are equal to one another . ' 7. ' Things which are halves of the same thing are equal to one another . ' These axioms may of course be extended to any multiple or fraction . Axioms 2-5 form a second connected ...
Side 90
... double of △ DBC ( I. 34 ) . ..grams are equal . Cases II . and III . A AEBA DFC ( I. 4 , I. 8 , I. 26 ) . △ DFC + || gram ADCB = ^ AEB + || gram EFCB . .. || gram ADCB = ram EFCB ( ax . 3 ) . ( N.B. Equal parts of the triangles . AE ...
... double of △ DBC ( I. 34 ) . ..grams are equal . Cases II . and III . A AEBA DFC ( I. 4 , I. 8 , I. 26 ) . △ DFC + || gram ADCB = ^ AEB + || gram EFCB . .. || gram ADCB = ram EFCB ( ax . 3 ) . ( N.B. Equal parts of the triangles . AE ...
Side 92
... double of the triangle . For each of the parallelograms in the figure is double of one of the triangles ( I. 34 ) , and since the triangles are equal , each parallelogram must be double of either triangle . This corollary is enunciated ...
... double of the triangle . For each of the parallelograms in the figure is double of one of the triangles ( I. 34 ) , and since the triangles are equal , each parallelogram must be double of either triangle . This corollary is enunciated ...
Side 95
... double of any triangle on the same base and between the same parallels as itself . Then , if we can divide the given triangle into two equal triangles , we can construct a parallelogram double of either of these ( as in I. 37 ) and ...
... double of any triangle on the same base and between the same parallels as itself . Then , if we can divide the given triangle into two equal triangles , we can construct a parallelogram double of either of these ( as in I. 37 ) and ...
Side 96
... double of triangle AEC ( I. 41 ) , and therefore equal to triangle ABC . B E C The problem is thus parallelogram ( i.e. its It follows from this proposition that any triangle may be divided into two others of equal area , by bisecting ...
... double of triangle AEC ( I. 41 ) , and therefore equal to triangle ABC . B E C The problem is thus parallelogram ( i.e. its It follows from this proposition that any triangle may be divided into two others of equal area , by bisecting ...
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Vanlige uttrykk og setninger
&c.-Q.E.D. PROPOSITION ABCD alternate angles angle ABC angle ACB angles are equal angles equal base BC bisected Cheaper Edition circle cons construction Demy 8vo diameter enunciation equal bases equal in area equal sides equal triangles equilateral triangle Euclid exterior Fcap Frontispiece given angle given line given point given straight line given triangle gnomon gram half the line Illustrations interior and opposite interior angles isosceles triangle Join line equal meet opposite angles opposite sides parallelogram perpendicular Poems problem produced proof Prop rectangle contained rhombus right angles right-angled triangle Second Edition sides equal Small crown 8vo square on AC square on half SUMMARY OF PROPOSITION THEOREM Third Edition Translated triangle ABC triangles are equal twice the rect twice the rectangle vertical angle vols Wherefore whole line
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Side 10 - HAWEIS, Rev. HR, MA— Current Coin. Materialism— The Devil — Crime — Drunkenness — Pauperism — Emotion — Recreation —The Sabbath.
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Side 6 - The Doctrine of Last Things contained in the New Testament compared with the Notions of the Jews and the Statements of Church Creeds.
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