The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected, and Some of Euclid's Demonstrations are Restored. Also, The Book of Euclid's Data, in Like Manner Corrected. viz. the first six books, together with the eleventh and twelfthMathew Carey, and sold by J. Conrad & Company, S. F. Bradford, Birch & Small, and Samuel Etheridge. Printed by T. & G. Palmer, 116, High-Street., 1806 - 518 sider |
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Resultat 1-5 av 11
Side 51
... gnomon . Thus the pa- rallelogram HG , together ' with the complements AF , ' FC , is the gnomon , which ' is more briefly expressed by the letters AGK , or EHC , which are at the B ' opposite angles of the pa- rallelograms which make ...
... gnomon . Thus the pa- rallelogram HG , together ' with the complements AF , ' FC , is the gnomon , which ' is more briefly expressed by the letters AGK , or EHC , which are at the B ' opposite angles of the pa- rallelograms which make ...
Side 55
... gnomon CMG ; therefore the gnomon CMG is equal to the rectangle AD , DB : to each of these add LG , which is equal e to the square of CD ; therefore the gnomon CMG , together with LG , is equal to the rectangle AD , DB , together ...
... gnomon CMG ; therefore the gnomon CMG is equal to the rectangle AD , DB : to each of these add LG , which is equal e to the square of CD ; therefore the gnomon CMG , together with LG , is equal to the rectangle AD , DB , together ...
Side 56
... gnomon CMG : and AM is the rect- angle contained by AD , DB , E GF e Cor . 4.2 . for DM is equale to DB : therefore the gnomon CMG is equal to the rectangle AD , DB : add to each of these LG , which is equal to the square of CB ...
... gnomon CMG : and AM is the rect- angle contained by AD , DB , E GF e Cor . 4.2 . for DM is equale to DB : therefore the gnomon CMG is equal to the rectangle AD , DB : add to each of these LG , which is equal to the square of CB ...
Side 57
... gnomon AKF together with the square CK ; therefore the gnomon AKF , toge- ther with the square CK , is double H of AK : but twice the rectangle AB , BC is double of AK , for BK is equal to BC : therefore the gnomon AKF , together ...
... gnomon AKF together with the square CK ; therefore the gnomon AKF , toge- ther with the square CK , is double H of AK : but twice the rectangle AB , BC is double of AK , for BK is equal to BC : therefore the gnomon AKF , together ...
Side 58
... gnomon AOH are quadruple of AK : and because AK is the rectangle contained by AB , BC , for BK is equal to BC , four ... gnomon AOH . To each of these add XH , which is equal d to the square of AC : therefore four times the ...
... gnomon AOH are quadruple of AK : and because AK is the rectangle contained by AB , BC , for BK is equal to BC , four ... gnomon AOH . To each of these add XH , which is equal d to the square of AC : therefore four times the ...
Vanlige uttrykk og setninger
altitude angle ABC angle BAC base BC BC is equal BC is given bisected Book XI centre circle ABCD circumference cone cylinder demonstrated described diameter draw drawn equal angles equiangular equimultiples Euclid excess fore given angle given in magnitude given in position given in species given magnitude given point given ratio given straight line gnomon greater join less Let ABC meet multiple opposite parallel parallelogram parallelogram AC perpendicular point F polygon prism proposition pyramid Q. E. D. PROP radius rectangle CB rectangle contained rectilineal figure remaining angle right angles segment sides BA similar solid angle solid parallelepipeds square of AC straight line AB straight line BC tangent THEOR third triangle ABC triplicate ratio vertex wherefore
Populære avsnitt
Side 28 - Any two sides of a triangle are together greater than the third side.
Side 62 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.
Side 28 - IF, from the ends of the side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than the other two sides of the triangle, but shall contain a greater angle. Let...
Side 57 - PROP. VIII. THEOR. IF a straight line be divided into any two parts, tour times the rectangle contained by the whole line, and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.
Side 26 - If one side of a triangle be produced, the exterior angle is greater than either of the interior opposite angles.
Side 163 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 17 - THE angles at the base of an isosceles triangle are equal to one another : and, if the equal sides be produced, the angles upon the other side of the base shall be equal.
Side 189 - In right angled triangles, the rectilineal figure described upon the side opposite to the right angle, is equal to the similar, and similarly described figures upon the sides containing the right angle.
Side 37 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sidef. For any rectilineal figure ABCDE can be divided into as many triangles as the figure has sides, by drawing straight lines from a point F within the figure to each of its angles.
Side 178 - Therefore, universally, similar rectilineal figures are to one another in the duplicate ratio of their homologous sides.