Trigonometry: Plane and Spherical; with the Construction and Application of Logarithms. By Thomas Simpson, F.R.S. |
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Resultat 1-5 av 5
Side 15
COROLLARY II . Hence , if ' the mean arch AC ' be supposed that of 60 ° ; then Of
being the co - fine of 60 ° , = ' sine 30 ° = 1 chord of 60 " = TOC , it is manifest that
DG - BE will , in this case , be barely = Dm ; and consequently DG = Dm + BE .
COROLLARY II . Hence , if ' the mean arch AC ' be supposed that of 60 ° ; then Of
being the co - fine of 60 ° , = ' sine 30 ° = 1 chord of 60 " = TOC , it is manifest that
DG - BE will , in this case , be barely = Dm ; and consequently DG = Dm + BE .
Side 23
... be conceived to pass , and thereby form two spherical triangles ABC and FCE ,
the latter of the triangles so formed is said to be the complement of the former ;
and vice versa . F E C B C4 COROL1 COROLLARIES . 1. It is manifest ( from Def
.
... be conceived to pass , and thereby form two spherical triangles ABC and FCE ,
the latter of the triangles so formed is said to be the complement of the former ;
and vice versa . F E C B C4 COROL1 COROLLARIES . 1. It is manifest ( from Def
.
Side 24
Plane and Spherical; with the Construction and Application of Logarithms. By
Thomas Simpson, F.R.S. Thomas Simpson. 1 COROLLARIES . 1. It is manifest (
from Def . 1. ) that the section of two great - circles ( as it passes through the
center ) ...
Plane and Spherical; with the Construction and Application of Logarithms. By
Thomas Simpson, F.R.S. Thomas Simpson. 1 COROLLARIES . 1. It is manifest (
from Def . 1. ) that the section of two great - circles ( as it passes through the
center ) ...
Side 31
... and EF and OK perpendicular to AO , and let the latter meet EC ( produced ) in
I ; lastly , draw QDK perpendicular to OD , meeting OA , OC and Ol ( produced )
inQ , Land K. Because CD = BD , it is manifest that OD is not only perpendicular ...
... and EF and OK perpendicular to AO , and let the latter meet EC ( produced ) in
I ; lastly , draw QDK perpendicular to OD , meeting OA , OC and Ol ( produced )
inQ , Land K. Because CD = BD , it is manifest that OD is not only perpendicular ...
Side 65
From whence it is manifest , that CD will be equal to half the sum , and AD equal
to half the difference , of the two sides of the triangle . Moreover , because of the
similar triangles AEH and HCD , it will be , AE : .CD2 :: HA ? -HEX HG ( by Cor . to
...
From whence it is manifest , that CD will be equal to half the sum , and AD equal
to half the difference , of the two sides of the triangle . Moreover , because of the
similar triangles AEH and HCD , it will be , AE : .CD2 :: HA ? -HEX HG ( by Cor . to
...
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Vanlige uttrykk og setninger
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