Trigonometry: Plane and Spherical; with the Construction and Application of Logarithms. By Thomas Simpson, F.R.S. |
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Resultat 1-5 av 5
Side 8
T C For , let ABC be the triangle , and AB and AC the А. two proposed fides ; F
and from the cenD ter A , with the vadius AB , let a circle be described , in .
tersecting CA pro6 dụced , in D and F ; so that CF may express the sum , and CD
the ...
T C For , let ABC be the triangle , and AB and AC the А. two proposed fides ; F
and from the cenD ter A , with the vadius AB , let a circle be described , in .
tersecting CA pro6 dụced , in D and F ; so that CF may express the sum , and CD
the ...
Side 9
Therefore in this case our proportion will become , АС АСь Radius : tang . ( =
ABC - 45 ° ) :: ABC + ACB ABC - ACB tangWhich gives the following Theorem ,
for finding the angles opposite to any two proposed sides , the in- . cluded angle ,
and ...
Therefore in this case our proportion will become , АС АСь Radius : tang . ( =
ABC - 45 ° ) :: ABC + ACB ABC - ACB tangWhich gives the following Theorem ,
for finding the angles opposite to any two proposed sides , the in- . cluded angle ,
and ...
Side 12
T D H E Let AE be the proposed arch , EF its fine , CF its co - fine , AF its versed
line , AT its tangent , CT its fecant , DH its co - tangent , and CH its co - fecant .
Then ( by 8. 2. ) we have CF = the square root of CE - EF ; wherce , not only the
co ...
T D H E Let AE be the proposed arch , EF its fine , CF its co - fine , AF its versed
line , AT its tangent , CT its fecant , DH its co - tangent , and CH its co - fecant .
Then ( by 8. 2. ) we have CF = the square root of CE - EF ; wherce , not only the
co ...
Side 31
I D For , let AB and K AC be the two proposed arches , and I ler BG and CH be
their fines , and OG S and OH their cofines : imoreover , B В let the arch BC be
equally divided in D , fo that CD may 1 11 GA be half the dif . ference , and AD
half ...
I D For , let AB and K AC be the two proposed arches , and I ler BG and CH be
their fines , and OG S and OH their cofines : imoreover , B В let the arch BC be
equally divided in D , fo that CD may 1 11 GA be half the dif . ference , and AD
half ...
Side 44
Let it be proposed to find the hyperbolic logarithm of the number 2 . Here x being
= , and x == ; we 2x3 + 2 I I fhall have 45 77 * ( = ) $ ) = , 333333333 & c . * ] ( = **
) 1037037037 & c . ** ? ) = , 004115226 & c . ** ) = 3000457247 & c . * = ** ?
Let it be proposed to find the hyperbolic logarithm of the number 2 . Here x being
= , and x == ; we 2x3 + 2 I I fhall have 45 77 * ( = ) $ ) = , 333333333 & c . * ] ( = **
) 1037037037 & c . ** ? ) = , 004115226 & c . ** ) = 3000457247 & c . * = ** ?
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Vanlige uttrykk og setninger
added alſo appears arch balf baſe becauſe called caſe chord circle co-f co-fine AC co-tang common complement conſequently COROL COROLLARY demonſtrated determine diameter difference divided drawn Edition equal equal to half evident exceſs extremes fame fides fine fines firſt follows given gives gles great-circles greater half the difference half the ſum Hence hyperbolic logarithm hypothenuſe known laſt logarithm manifeſt meeting method minute Moreover natural Note oppoſite parallel perpendicular plane triangle ABC preceding PROP proportion propoſed radius reſpectively ſame ſecant ſee ſeries ſhall ſides ſince ſine ſum ſuppoſed tang tangent of half Tbeor Theor THEOREM thereof theſe thoſe unity verſed vertical angle whence