Primary Elements of Plane and Solid Geometry: For Schools and AcademiesWilson, Hinkle & Company, 1862 - 98 sider |
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Side 28
... Schol . Any side , as AB , of a parallelogram may be taken as its base ; and a per- pendicular , as CE , let fall A4 from any point in the oppo- site parallel on the base , or the base produced , is called the altitude of the ...
... Schol . Any side , as AB , of a parallelogram may be taken as its base ; and a per- pendicular , as CE , let fall A4 from any point in the oppo- site parallel on the base , or the base produced , is called the altitude of the ...
Side 29
... Schol . If a quadrilateral has its opposite sides equal it is a parallelogram . For the triangles ABC , ADC , will in that case be mutually equilateral , and there- fore equal ( Cor . , Theo . XII ) ; and the parallelism of the opposite ...
... Schol . If a quadrilateral has its opposite sides equal it is a parallelogram . For the triangles ABC , ADC , will in that case be mutually equilateral , and there- fore equal ( Cor . , Theo . XII ) ; and the parallelism of the opposite ...
Side 30
... , the whole number of square units in ABCD is equal to the number of linear units in AB multiplied by the number of linear units in AD . Hence , the area of a rectangle , etc. Schol . If AB and AD are incommensurable , that 30 GEOMETRY .
... , the whole number of square units in ABCD is equal to the number of linear units in AB multiplied by the number of linear units in AD . Hence , the area of a rectangle , etc. Schol . If AB and AD are incommensurable , that 30 GEOMETRY .
Side 31
For Schools and Academies Evan Wilhelm Evans. Schol . If AB and AD are incommensurable , that is , if no unit can be found into which they can both be divided without leaving a remainder in one of them , the theorem will still hold true ...
For Schools and Academies Evan Wilhelm Evans. Schol . If AB and AD are incommensurable , that is , if no unit can be found into which they can both be divided without leaving a remainder in one of them , the theorem will still hold true ...
Side 36
... Schol . The area of a polygon may be found by dividing it into triangles as above ( or by diagonals drawn from any angle A to the opposite angles ) , then finding the areas of these triangles separately and adding them together ...
... Schol . The area of a polygon may be found by dividing it into triangles as above ( or by diagonals drawn from any angle A to the opposite angles ) , then finding the areas of these triangles separately and adding them together ...
Andre utgaver - Vis alle
Primary Elements of Plane and Solid Geometry: For Schools and Academies Evan Wilhelm Evans Uten tilgangsbegrensning - 1862 |
Primary Elements of Plane and Solid Geometry: For Schools and Academies E W (Evan Wilhelm) 1827-1874 Evans Ingen forhåndsvisning tilgjengelig - 2021 |
Primary Elements of Plane and Solid Geometry: For Schools and Academies E. W. 1827-1874 Evans Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
AB² ABCDEF allel alternate angles altitude angle BAC angles ABC apothegm base multiplied bisect called chord circle circumference cone consequently convex surface diagonals diameter divided draw Eclectic Reader equal Theo equal to half equivalent frustum Geometry given point half the arc half the product Hence hypotenuse included angle inscribed angle intersect isosceles triangle Let ABCD let fall McGuffey's measured by half mutually equiangular mutually equilateral number of equal number of sides opposite parallelogram perimeter perpendicular perpendicular distance prism proportion proved Published by W. B. quadrilateral radii radius Ray's rectangle regular inscribed regular polygon regular pyramid right angles right parallelopiped right-angled triangle Schol semicircle side BC slant hight solidity square straight line SUPT tangent THEOREM trapezoid triangles ABC triangles are equal triangular vertex W. B. SMITH
Populære avsnitt
Side 69 - If from a point without a circle, a tangent and a secant be drawn, the tangent will be a mean proportional between the secant and its external segment.
Side 42 - The circumference of every circle is supposed to' be divided into 360 equal parts, called degrees ; each degree into 60 minutes, and each minute into 60 seconds. Degrees, minutes, and seconds are designated by the characters °, ', ". Thus 23° 14' 35" is read 23 degrees, 14 minutes, and 35 seconds.
Side 21 - If two triangles have two sides, and the included angle of the one equal to two sides and the included angle of the other, each to each, the two triangles are equal in all respects.
Side 47 - It follows, then, that the area of a circle is equal to half the product of its circumference and its radius.
Side 72 - The areas of two circles are to each other as the squares of their radii. For, if S and S' denote the areas, and R and R
Side 33 - The square described on the hypothenuse of a right-angled triangle is equivalent to the sum of the squares described on the other two sides.
Side 38 - The area of a regular polygon is equal to half the product of its apothem and perimeter.
Side 52 - PROBLEM VII. Two angles of a triangle being given, to find the third angle. The three angles of every triangle are together equal to two right angles (Prop.
Side 30 - The area of a rectangle is equal to the product of its base and altitude.
Side 69 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...