Primary Elements of Plane and Solid Geometry: For Schools and AcademiesWilson, Hinkle & Company, 1862 - 98 sider |
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Resultat 1-5 av 13
Side 24
... describe the triangle DGF equal to the triangle ABC , and so placed that DG shall be the side equal to AB . Now , the sum of DH and HG is greater than DG ( Ax . 10 ) ; and the sum of EH and HF is greater than EF . Therefore , the sum of ...
... describe the triangle DGF equal to the triangle ABC , and so placed that DG shall be the side equal to AB . Now , the sum of DH and HG is greater than DG ( Ax . 10 ) ; and the sum of EH and HF is greater than EF . Therefore , the sum of ...
Side 49
... describe the arc CFD . From B as a center , with the E F B D same radius , describe the arc CED . Join the points of intersection C and D. Evans ' Geometry . - 5 Now , since the opposite sides of the quadrilateral ACBD BOOK I. 49 Sec IX ...
... describe the arc CFD . From B as a center , with the E F B D same radius , describe the arc CED . Join the points of intersection C and D. Evans ' Geometry . - 5 Now , since the opposite sides of the quadrilateral ACBD BOOK I. 49 Sec IX ...
Side 50
... describe an arc ; and from E as a center , with the same radius , describe another arc intersecting the former at some point F. Now , draw FC , and it will be the perpendicular required . Join FD and FE . Then , since the triangles DFC ...
... describe an arc ; and from E as a center , with the same radius , describe another arc intersecting the former at some point F. Now , draw FC , and it will be the perpendicular required . Join FD and FE . Then , since the triangles DFC ...
Side 51
... From C BF C , as a center , with any radius as CB , describe an are BA intersecting both the sides of the angle ; also , draw the chord BA . Then , from F as a center , with a radius FE equal to CB , draw an indefinite BOOK I. 51.
... From C BF C , as a center , with any radius as CB , describe an are BA intersecting both the sides of the angle ; also , draw the chord BA . Then , from F as a center , with a radius FE equal to CB , draw an indefinite BOOK I. 51.
Side 53
... describe an arc inter- secting BC at D. Join AD . B It is evident that ABD is the triangle required . PROBLEM IX . To draw a circle through three given points . Solution . Let A , B , and C be the given points . Draw the straight lines ...
... describe an arc inter- secting BC at D. Join AD . B It is evident that ABD is the triangle required . PROBLEM IX . To draw a circle through three given points . Solution . Let A , B , and C be the given points . Draw the straight lines ...
Andre utgaver - Vis alle
Primary Elements of Plane and Solid Geometry: For Schools and Academies Evan Wilhelm Evans Uten tilgangsbegrensning - 1862 |
Primary Elements of Plane and Solid Geometry: For Schools and Academies E W (Evan Wilhelm) 1827-1874 Evans Ingen forhåndsvisning tilgjengelig - 2021 |
Primary Elements of Plane and Solid Geometry: For Schools and Academies E. W. 1827-1874 Evans Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
AB² ABCDEF allel alternate angles altitude angle BAC angles ABC apothegm base multiplied bisect called chord circle circumference cone consequently convex surface diagonals diameter divided draw Eclectic Reader equal Theo equal to half equivalent frustum Geometry given point half the arc half the product Hence hypotenuse included angle inscribed angle intersect isosceles triangle Let ABCD let fall McGuffey's measured by half mutually equiangular mutually equilateral number of equal number of sides opposite parallelogram perimeter perpendicular perpendicular distance prism proportion proved Published by W. B. quadrilateral radii radius Ray's rectangle regular inscribed regular polygon regular pyramid right angles right parallelopiped right-angled triangle Schol semicircle side BC slant hight solidity square straight line SUPT tangent THEOREM trapezoid triangles ABC triangles are equal triangular vertex W. B. SMITH
Populære avsnitt
Side 69 - If from a point without a circle, a tangent and a secant be drawn, the tangent will be a mean proportional between the secant and its external segment.
Side 42 - The circumference of every circle is supposed to' be divided into 360 equal parts, called degrees ; each degree into 60 minutes, and each minute into 60 seconds. Degrees, minutes, and seconds are designated by the characters °, ', ". Thus 23° 14' 35" is read 23 degrees, 14 minutes, and 35 seconds.
Side 21 - If two triangles have two sides, and the included angle of the one equal to two sides and the included angle of the other, each to each, the two triangles are equal in all respects.
Side 47 - It follows, then, that the area of a circle is equal to half the product of its circumference and its radius.
Side 72 - The areas of two circles are to each other as the squares of their radii. For, if S and S' denote the areas, and R and R
Side 33 - The square described on the hypothenuse of a right-angled triangle is equivalent to the sum of the squares described on the other two sides.
Side 38 - The area of a regular polygon is equal to half the product of its apothem and perimeter.
Side 52 - PROBLEM VII. Two angles of a triangle being given, to find the third angle. The three angles of every triangle are together equal to two right angles (Prop.
Side 30 - The area of a rectangle is equal to the product of its base and altitude.
Side 69 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...