The Teacher's Assistant in the "Course of Mathematics Adapted to the Method of Instruction in the American CollegesDurrie & Peck, 1836 - 472 sider |
Inni boken
Resultat 1-5 av 36
Side 10
... places whose distance is known , found ? What is the declination of the magnetic needle ? and how great is it at different places ? Is it uniform at the same places ? How may a true meridian be drawn ? CONIC SECTIONS . What is a cone ...
... places whose distance is known , found ? What is the declination of the magnetic needle ? and how great is it at different places ? Is it uniform at the same places ? How may a true meridian be drawn ? CONIC SECTIONS . What is a cone ...
Side 17
... Place the multiplier under the multipli- cand , so that the same orders may stand under each other . 2. Multiply the multiplicand by each significant figure in the multiplier , placing the first figure of each partial product under the ...
... Place the multiplier under the multipli- cand , so that the same orders may stand under each other . 2. Multiply the multiplicand by each significant figure in the multiplier , placing the first figure of each partial product under the ...
Side 18
... places on the left of the dividend as there are places in the divisor ; or if these be not sufficient , take one more . 3. Multiply the divisor by this quotient , place the product under the partial dividend , from which subtract it ...
... places on the left of the dividend as there are places in the divisor ; or if these be not sufficient , take one more . 3. Multiply the divisor by this quotient , place the product under the partial dividend , from which subtract it ...
Side 22
... place the root in the quotient , and to the remainder bring down the next peri- od for a dividend . 2. Double the root already found , ( un- derstanding a cypher at the right , ) for a divisor , and divide the dividend by it , for the ...
... place the root in the quotient , and to the remainder bring down the next peri- od for a dividend . 2. Double the root already found , ( un- derstanding a cypher at the right , ) for a divisor , and divide the dividend by it , for the ...
Side 27
... place the quantity over the radical sign belonging to the re- quired root . An odd root of any quantity has the same sign as the quantity itself . An even root of an affirmative quantity is ambiguous . An even root of a negative quanti ...
... place the quantity over the radical sign belonging to the re- quired root . An odd root of any quantity has the same sign as the quantity itself . An even root of an affirmative quantity is ambiguous . An even root of a negative quanti ...
Innhold
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Vanlige uttrykk og setninger
added answer arithmetical base body Changing signs circle circumference Clearing of fractions co-efficients Co-secant Co-sine Co-tangent Completing the square cot a cot Course Cube Roots denominator diameter Diff difference of latitude Dist distance Dividing divisor equal equation Euclid Extracting the square extremes and means feet find the angle find the area find the solidity frustum geometrical geometrical progression geometrical series given greater Hence hight hypothenuse inches less Let x=the logarithm magnitude Merid miles Multiplying extremes natural number belonging parallelogram parallelopiped perpendicular plane sailing polygon PROBLEM proportion quotient radius ratio rectangle contained Reduce right angles rods Secant sector segment Sine square root straight line Substi Substituting a's Substituting numbers Substituting y's value subtracted surface tables Tangent Theorem Transposing and uniting Trig velocity
Populære avsnitt
Side 36 - If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz. either the sides adjacent to the equal...
Side 49 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 42 - If a straight line touch a circle, and from the point of contact a straight line be drawn cutting the circle, the angles...
Side 39 - IF a straight line be divided into any two parts, four times the rectangle contained by the whole line, and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.
Side 38 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Side 37 - IF a straight line fall upon two parallel straight lines, it makes the alternate angles equal to one another; and the exterior angle equal to the interior and opposite upon the same side; and likewise the two interior angles upon the same side together equal to two right angles...
Side 38 - Prove it. 6.If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced, and the part of it produced together with the -square on half the line bisected, is equal to the square on the straight line which is made up of the half and the part produced.
Side 42 - IF from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.
Side 35 - Upon the same base, and on the same side of it, there cannot be two triangles, that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extremity, equal to one another.
Side 33 - Then divide the first term of the remainder by the first term of the divisor...