A treatise on navigation, and nautical astronomyBaldwin, Cradock, and Joy, 1824 - 551 sider |
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Resultat 1-5 av 71
Side 12
... computed . Having found in this manner the logarithms of all prime numbers , which are those that have no divisor ; as 2 , 3 , 5 , 7 , 11 , & c . the loga- rithms of all other numbers may easily be found . For , as 3 x 5 15 , the ...
... computed . Having found in this manner the logarithms of all prime numbers , which are those that have no divisor ; as 2 , 3 , 5 , 7 , 11 , & c . the loga- rithms of all other numbers may easily be found . For , as 3 x 5 15 , the ...
Side 66
... computed . As the sides and angles of triangles are quantities of different kinds , they cannot be compared with each other ; but the relation between the sides and the magnitude of the angles may be discovered by com- paring the sides ...
... computed . As the sides and angles of triangles are quantities of different kinds , they cannot be compared with each other ; but the relation between the sides and the magnitude of the angles may be discovered by com- paring the sides ...
Side 69
... computed to a given radius , these numbers would exhibit the ratios of the sines , tangents , & c . to any other radius . A table con- taining such numbers is called a table of natural sines , tangents , & c .; and a table exhibiting ...
... computed to a given radius , these numbers would exhibit the ratios of the sines , tangents , & c . to any other radius . A table con- taining such numbers is called a table of natural sines , tangents , & c .; and a table exhibiting ...
Side 76
... computed , the sines may easily be continued to 60 ° ; and then by the latter theorem , the sines of all arcs between 60 ° , and the quadrant will readily be obtained . The foregoing formulae might all have been investigated geome ...
... computed , the sines may easily be continued to 60 ° ; and then by the latter theorem , the sines of all arcs between 60 ° , and the quadrant will readily be obtained . The foregoing formulae might all have been investigated geome ...
Side 77
... computed . Now 60 ° is an arc of that description ; its cosine ( Proposition 1. Trig . ) being to radius unity . Hence cos 30 ° = cos 60 ° 2 = - √3 . In this way the 2 cosine of 15 ° , 7 ° 30 ′ , & c . may be computed ; till , after ...
... computed . Now 60 ° is an arc of that description ; its cosine ( Proposition 1. Trig . ) being to radius unity . Hence cos 30 ° = cos 60 ° 2 = - √3 . In this way the 2 cosine of 15 ° , 7 ° 30 ′ , & c . may be computed ; till , after ...
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A Treatise on Navigation and Nautical Astronomy ... Fourth edition, etc Edward Riddle Uten tilgangsbegrensning - 1842 |
Vanlige uttrykk og setninger
angled spherical triangle Answer apparent altitude Atlantic Ocean bisected Cape celestial object centre chronometer circle column compass computed correction Cosec Cosine Cotang course and distance declination diff lat diff long Difference of Latitude difference of longitude Dist equal equator EXAMPLES FOR EXERCISE Given A B greater Greenwich Hence horizontal parallax Indian Archipelago Indian Ocean Island Latitude and Departure latitude and longitude logarithm longitude Lunar Distance meridian distance miles moon moon's Nautical Almanac noon observed opposite Pacific Ocean parallax parallel parallel sailing parallelogram perpendicular plane sailing polar distance pole quadrant radius rectangle rhumb line right angled spherical right ascension Secant semidiameter sides squares of A C subtract Suvers Suversed Sines Table Tang tangent Theo THEOREM triangle A B C true altitude true distance Vers
Populære avsnitt
Side 18 - LET it be granted that a straight line may be drawn from any one point to any other point.
Side 17 - When equals are taken from unequals, the remainders are unequal. 6. Things which are double of the same thing, or equal things, are equal to each other.
Side 86 - III.), is a circle. If the plane pass through the centre, then, as every point in the surface of the sphere is equidistant from its centre, the section is a plane figure, every point of whose periphery is equidistant from a certain point within it, and the figure is therefore a circle. But if the plane do not pass through...
Side 26 - Therefore all the interior angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 114 - TO THEIR DIFFERENCE ; So IS THE TANGENT OF HALF THE SUM OF THE OPPOSITE ANGLES', To THE TANGENT OF HALF THEIR DIFFERENCE.
Side 63 - If from a point without a circle two straight lines be drawn, one of which...
Side 147 - Mathematical o>jgraphy.) the arc of the equator, intercepted between the first meridian...
Side 64 - If from any point without a circle straight lines be drawn touching it, the angle contained by the tangents is double the angle contained by the straight line joining the points of contact and the diameter drawn through one of them.
Side 139 - Given the vertical angle, the difference of the two sides containing it, and the difference of the segments of the base made by a perpendicular from the vertex ; construct the triangle.
Side 86 - ... half a right angle, as the tangent of half the sum of the angles, at the base of the triangle to the tangent of half their difference.