## Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids; to which are Added Elements of Plane and Spherical TrigonometryW. E. Dean, 1851 - 317 sider |

### Inni boken

Resultat 1-5 av 40

Side 21

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**bisected**, it may be demonstrated that the angle BCG , that is ( 15. 1. ) , the angle ACD , is greater than the angle ABC . B E F D PROP . XVII . THEOR . Any two angles of a triangle are together less than two right angles . Let ABC be ... Side 52

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**bisected**, and produced to any point ; the rectangle contained by the whole line thus produced , and the part of it produced , together with the square of half the line**bisected**, is equal to the square of the straight line which is ... Side 55

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**bisected**, and of the square of the line made up of the half and the part produced . Let the straight line AB be**bisected**in C , and produced to the point D ; the squares of AD , DB are double of the squares of AC , CD . From the point ... Side 56

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**bisect**( 10. 1. ) AC in E , and join BE ; produce CA to F , and make ( 3. 1. ) EF equal to EB , and upon AF describe ...**bisected**in E , and produced to the point F , the rectangle CF.FA , to- gether with the square of AE , is equal ( 6 ... Side 59

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**bisected**, the sum of the squares of the other two sides is double of the square of half the side**bisected**, and of the square of the line drawn from the point of**bisection**to the opposite angle of the triangle . Let ABC be a triangle ...### Andre utgaver - Vis alle

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Elements of Geometry: Containing the First Six Books of Euclid, with a ... John Playfair Uten tilgangsbegrensning - 1836 |

### Vanlige uttrykk og setninger

ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated described diameter divided draw equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given rectilineal given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROB PROP proportional proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR touches the circle triangle ABC triangle DEF wherefore