Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids; to which are Added Elements of Plane and Spherical TrigonometryW. E. Dean, 1851 - 317 sider |
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Side 12
... straight line . Let AB be the given straight line ; it is required to ... BC is equal to AB : But it has been proved that CA is equal to AB ... straight line AB . PROP . II . PROB . From a given point to draw a straight line ...
... straight line . Let AB be the given straight line ; it is required to ... BC is equal to AB : But it has been proved that CA is equal to AB ... straight line AB . PROP . II . PROB . From a given point to draw a straight line ...
Side 13
... straight line AL is equal to BC . Wherefore , from the given point A , a straight line AL has been drawn equal to the given straight line BC . PROP . III . PROB . From the greater of two given straight lines to cut off a part equal ...
... straight line AL is equal to BC . Wherefore , from the given point A , a straight line AL has been drawn equal to the given straight line BC . PROP . III . PROB . From the greater of two given straight lines to cut off a part equal ...
Side 16
... straight line BC upon EF ; the point C shall also coincide with the point F , because BC is equal to EF : therefore BC coin- ciding with EF , BA and AC shall coincide with ED and DF ; for , if BA and CA do not coincide with ED and FD ...
... straight line BC upon EF ; the point C shall also coincide with the point F , because BC is equal to EF : therefore BC coin- ciding with EF , BA and AC shall coincide with ED and DF ; for , if BA and CA do not coincide with ED and FD ...
Side 17
... BC coincides with the base EF , the sides BA , AC cannot but coincide with ... straight line AF bisects the angle BAC . Because AD is equal to AE , and AF ... straight line AF . E F B C SCHOLIUM . By the same construction , each ...
... BC coincides with the base EF , the sides BA , AC cannot but coincide with ... straight line AF bisects the angle BAC . Because AD is equal to AE , and AF ... straight line AF . E F B C SCHOLIUM . By the same construction , each ...
Side 19
... straight line makes with another upon one side of it , are either two right angles , or are together equal to two ... BC , BD upon the opposite sides of AB , make the adja- cent angles ABC , ABD equal togethe . to two right angles . BD is in ...
... straight line makes with another upon one side of it , are either two right angles , or are together equal to two ... BC , BD upon the opposite sides of AB , make the adja- cent angles ABC , ABD equal togethe . to two right angles . BD is in ...
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Vanlige uttrykk og setninger
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated described diameter divided draw equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given rectilineal given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROB PROP proportional proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR touches the circle triangle ABC triangle DEF wherefore