Elementary Geometry, Plane and Solid: For Use in High Schools and AcademiesMacmillan, 1901 - 440 sider |
Inni boken
Resultat 1-5 av 100
Side 10
... Hence in whatever position the line CD is drawn the sum of the two adjacent angles BCD and ACD is always equal to two right angles . If the line CD should cross AB , the sum of the two angles on the other side of AB would also be equal ...
... Hence in whatever position the line CD is drawn the sum of the two adjacent angles BCD and ACD is always equal to two right angles . If the line CD should cross AB , the sum of the two angles on the other side of AB would also be equal ...
Side 12
... Hence they must coincide throughout . Art . 4 . Therefore any one straight angle is equal to any other straight angle ; or , all straight angles are equal . Since a right angle is always half of a straight angle , and all straight ...
... Hence they must coincide throughout . Art . 4 . Therefore any one straight angle is equal to any other straight angle ; or , all straight angles are equal . Since a right angle is always half of a straight angle , and all straight ...
Side 24
... Hence AC equals BC . ( Axiom 1 ) Therefore AB , AC , BC are all equal , and the triangle ABC is equilateral . EXERCISES 1. Is this proposition a problem or a theorem ? 2. If F is the other point of intersection of the two circles , and ...
... Hence AC equals BC . ( Axiom 1 ) Therefore AB , AC , BC are all equal , and the triangle ABC is equilateral . EXERCISES 1. Is this proposition a problem or a theorem ? 2. If F is the other point of intersection of the two circles , and ...
Side 26
... hence AC equals m . All radii of a circle are equal by definition . ( See Art . 25. ) The side BC is a radius of the circle CEF , hence BC equals m . Explain why . The side AB was constructed equal to n . Hence the triangle CAB fulfils ...
... hence AC equals m . All radii of a circle are equal by definition . ( See Art . 25. ) The side BC is a radius of the circle CEF , hence BC equals m . Explain why . The side AB was constructed equal to n . Hence the triangle CAB fulfils ...
Side 27
... [ why ? ] ; and the side AB was chosen equal to the given line - segment m . Hence the triangle CAB fulfils the given conditions . EXERCISES 1. Under what conditions would the circle CDE pass 37-39 ] TRIANGLES AND PARALLELOGRAMS 27 27.
... [ why ? ] ; and the side AB was chosen equal to the given line - segment m . Hence the triangle CAB fulfils the given conditions . EXERCISES 1. Under what conditions would the circle CDE pass 37-39 ] TRIANGLES AND PARALLELOGRAMS 27 27.
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Andre utgaver - Vis alle
Elementary Geometry, Plane and Solid: For Use in High Schools and Academies Thomas Franklin Holgate Uten tilgangsbegrensning - 1901 |
Elementary Geometry, Plane and Solid; for Use in High Schools and Academies Thomas F 1859-1945 Holgate Ingen forhåndsvisning tilgjengelig - 2018 |
Elementary Geometry Plane and Solid: For Use in High Schools and Academies Thomas F. Holgate Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
ABCD adjacent angles altitude angle formed apothem base bisector bisects called centre chord circumscribed coincide common convex convex polygon COROLLARY DEFINITION diagonals diameter dicular dihedral angle draw equal angles equal in area equiangular equidistant EXERCISES face angles figure given circle given line-segment given plane given point given straight line greater Hence hypotenuse identically equal interior angles isosceles triangle lateral area lateral edges lateral surface length magnitudes measure meet mid-point number of sides opposite sides parallel planes parallelepiped parallelogram pass perimeter perpen plane angles point of intersection polyhedral angle polyhedron prism Proof Prop PROPOSITION pyramid quadrilateral radii radius ratio rectangle regular polygon required to prove respectively right triangle segment side BC similar sphere spherical angle spherical polygon spherical triangle square subtended supplementary angle tangent tetrahedron theorem triangle ABC triangle is equal trihedral vertex volume
Populære avsnitt
Side 187 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 207 - The formula states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the base and altitude.
Side 78 - The line which joins the mid-points of two sides of a triangle is parallel to the third side and equal to one half of it.
Side 45 - Prove that, if two sides of a triangle are unequal, the angle opposite the greater side is greater than the angle opposite the less.
Side 231 - A polygon of three sides is called a triangle ; one of four sides, a quadrilateral; one of five sides, a, pentagon; one of six sides, a hexagon ; one of seven sides, a heptagon ; one of eight sides, an octagon ; one of ten sides, a decagon ; one of twelve sides, a dodecagon.
Side 95 - If two triangles have two sides of the one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side of the first is greater than the third side of the second. Given A ABC and A'B'C...
Side 200 - The area of a triangle is equal to half the product of its base by its altitude.
Side 161 - ... they have an angle of one equal to an angle of the other and the including sides are proportional; (c) their sides are respectively proportional.
Side 201 - Two parallelograms are similar when they have an angle of the one equal to an angle of the other, and the including sides proportional.
Side 29 - If two triangles have two sides, and the included angle of the one equal to two sides and the included angle of the other, each to each, the two triangles are equal in all respects.