Elements of Geometry: With, Practical ApplicationsD. Appleton and Company, 1850 - 320 sider |
Inni boken
Resultat 1-5 av 100
Side 8
... Hence , the ex- tremities of lines are points . Also , the place of inter- section of two lines is a point . ( 2. ) The common notion of a point is derived from the extremity of some slender body , such as the end of a common sewing ...
... Hence , the ex- tremities of lines are points . Also , the place of inter- section of two lines is a point . ( 2. ) The common notion of a point is derived from the extremity of some slender body , such as the end of a common sewing ...
Side 20
... Hence , also , conversely , if the two angles ADC , BDC , on the same side of the line AB , make up together two right - angles , then AD and DB will form a continued straight line AB . Cor . 2. Hence , all the angles which can be made ...
... Hence , also , conversely , if the two angles ADC , BDC , on the same side of the line AB , make up together two right - angles , then AD and DB will form a continued straight line AB . Cor . 2. Hence , all the angles which can be made ...
Side 23
... hence the angle BGD is equal to AGC . Which is necessary , that the angle of incidence and the angle of reflection of the light may be equal . ( 30. ) Suppose AC and BD to represent two trees standing on the horizontal plane AB , it is ...
... hence the angle BGD is equal to AGC . Which is necessary , that the angle of incidence and the angle of reflection of the light may be equal . ( 30. ) Suppose AC and BD to represent two trees standing on the horizontal plane AB , it is ...
Side 28
... to the whole ; ( Ax . VIII ; ) hence there can be no inequality between the sides CB and CA , and therefore the triangle is isos- celes . PROPOSITION VIII . THEOREM . When two triangles have the 28 ELEMENTS OF GEOMETRY .
... to the whole ; ( Ax . VIII ; ) hence there can be no inequality between the sides CB and CA , and therefore the triangle is isos- celes . PROPOSITION VIII . THEOREM . When two triangles have the 28 ELEMENTS OF GEOMETRY .
Side 33
... hence ( Prop . VIII , ) the angles ABD and CBD are equal . PROPOSITION XII . PROBLEM . Through a given point C , in a given line AB , to draw a perpendicular . Take equal distances CD , CF , on each side of the given point ; and with ...
... hence ( Prop . VIII , ) the angles ABD and CBD are equal . PROPOSITION XII . PROBLEM . Through a given point C , in a given line AB , to draw a perpendicular . Take equal distances CD , CF , on each side of the given point ; and with ...
Andre utgaver - Vis alle
Elements of Geometry: With Practical Applications ... George Roberts Perkins Uten tilgangsbegrensning - 1847 |
Elements of Geometry: With Practical Applications Designed for Beginners George Roberts Perkins Uten tilgangsbegrensning - 1853 |
Elements of Geometry With Practical Applications George R Perkins Ingen forhåndsvisning tilgjengelig - 2023 |
Vanlige uttrykk og setninger
a+b+c altitude angle ABC angle BAC angle BCD bisect centre chord circ circular sector circumference circumscribed polygon coincide cone consequently convex surface cylinder denote diagonal diameter dicular distance draw equal and parallel equiangular equilateral triangle equivalent exterior angle figure formed given line greater half the arc hypothenuse inscribed circle intersection isosceles join less Let ABC line AC line CD lines drawn measured by half meet multiplied number of sides parallel planes parallelogram parallelopipedon pendicular perimeter perpen perpendicular plane MN point G prism PROBLEM produced Prop PROPOSITION pyramid radii radius rectangle regular polygon respectively equal right-angled triangle Sabc Schol Scholium scribed semicircle semicircumference side AC similar similar triangles solid angle sphere spherical triangle square straight line suppose tangent THEOREM three sides triangle ABC triangular prism vertex VIII
Populære avsnitt
Side 231 - THE sphere is a solid terminated by a curve surface, all the points of which are equally distant from a point within, called the centre.
Side 147 - PROBLEM. To inscribe a circle in a given triangle. Let ABC be the given triangle : it is required to inscribe a circle in the triangle ABC.
Side 17 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Side 28 - If two sides and the included angle of the one are respectively equal to two sides and the included angle of the other...
Side 233 - The volume of a cylinder is equal to the product of its base by its altitude. Let the volume of the cylinder be denoted by V, its base by B, and its altitude by H.
Side 276 - THEOREM. Two triangles on the same sphere, or on equal spheres, are equal in all their parts, when they have each an equal angle included between equal sides. Suppose the side...
Side 120 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Side 18 - If equals be added to unequals, the wholes are unequal. V. If equals be taken from unequals, the remainders are unequal. VI. Things which are double of the same, are equal to one another.
Side 232 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Side 96 - Similar figures, are those that have all the angles of the one equal to all the angles of the other, each to each, and the sides about the equal angles proportional.