 | William Nicholson - 1809 - 722 sider
...add the sqnare of its height ; multiply the sum by the height, and the product by .r>'236.' Or, 2<Uy, From three times the diameter of the sphere, subtract twice the height of the fribtnim ; multiply the remaintier by the square of the height, and the product by .5236. SEGUIERIA,... | |
 | Charles Hutton - 1815 - 686 sider
...the square of its height ; multiply the sum by the height, and the product by '5236. Or, 2dly, From 3 times the diameter of the sphere, subtract twice the height of the frustum ; multiply the remainder by the square of the height, and the product by '5236. That is, in... | |
 | Thomas Keith - 1817 - 306 sider
...tUe globe is the .greatest. PROBLEM XIII. Tojlnd the Solidity of the Segment of a Sphere. RULE 1 *. From three times the diameter of the sphere, subtract twice the height of the segment ; multiply * Demonstrauon. Let A cm represent a triangular pyramid, whose tide m A is infinitely small.... | |
 | William Nicholson - 1821 - 382 sider
...add the square of its height ; multiply the sum by the height, and the pioduct by .52J6. Or, 2dly, From three times the diameter of the sphere, subtract twice the height of the frustrum; multiply the remainder by the square of the height, and the product by .5236. SEGUIER1A,... | |
 | James Mitchell - 1823 - 666 sider
...add tile square of its height; multiply the sum by the height, and the product by -5236. Or, 2dly, From three times the diameter of the sphere, subtract twice the height of the frustrum ; multiply the remainder by the square of the height, and the product by -5236. That is, in... | |
 | Anthony Nesbit - 1824 - 476 sider
...this sum multiplied by the height, and the product again by .5236, will give the solidity. RULE II. From three times the diameter of the sphere subtract twice the height of the segment; multiply the remainder by the square of the height, and that pro-i duct by .5236 for the solidity,... | |
 | John Bonnycastle - 1829 - 256 sider
...and this sum multiplied by the height, and the product again by .5236, will give the solidity. Or, From three times the diameter of the sphere subtract twice the height of the segment, multiply by the square of the height, and that .product by .5236 ; the last product will be the solidity.... | |
 | Frederick Augustus Griffiths - 1839 - 348 sider
...find the solid content of a spherical segment. From three times the diameter of the sphere take double the height of the segment; then multiply the remainder by the square of the height, and this product by -5236. Or, To three times the square of the radius of the segment's base add the square... | |
 | Benjamin Greenleaf - 1844 - 208 sider
...the contents of a spherical segment. RULE. From three times the diameter of the sphere, take double the height of the segment ; then multiply the remainder by the square of the height, and tJie product by the decimal .5236 for the contents ; or to three times the square of the radius of... | |
 | William Watson (of Beverley.) - 1845 - 188 sider
...; or the square of the chord of half the arc by 3.1416. •f To find the solidity of a segment. — From three times the diameter of the sphere, subtract...remainder by the square of the height, and the product ~again by .5236. Or, to three times the square of the radius ot the base of the segment, add the square... | |
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From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236. 
