 | Thomas Hodson - 1806 - 502 sider
...FIG. g. The area of all triangles is found by- the following rules : — RULE i. Multiply the bafe by the perpendicular height, and half the product will be the area. But when only the three fides of the triangle are given, the area is found by the following rule: —... | |
 | Isaac Dalby - 1807 - 968 sider
...remaining shall be equal to 5 square 1ч i ? Ans. lOj'r inches. To find the urea of a Trianglt, 257. MULTIPLY the base by the perpendicular height, and half the product will be the area. Or multiply the base by half the height, or the height by halt the base. • For a triangle U equal... | |
 | Isaac Dalby - 1807 - 476 sider
...shall be equal to 5 square feet? Ans. 10TV inches. To find the urea of a Triangle. 257. MuLTiPLYthe base by the perpendicular height, and half the product will be the area. Or multiply the base by half the height, or the height by half the base. For a triangle is equal to... | |
 | James Thompson - 1808 - 176 sider
...whose length is 12 feet 6 inches, and its height 9 feet 3 inches ! Ata. 115/f. 7 in. 6". II. To ßnd the area of a triangle. RULE — Multiply the base...perpendicular height, and half the product will be theurea. EXAMPLES. 9. Required the area of the triangle whose base is 10 feet 9 inches, and height... | |
 | Peter Nicholson - 1809 - 426 sider
...whose length AB is l6f. 3i. and the height DE 5f. 6i. ? PROBLEM II. To find the area of a triangle. Multiply the base by the perpendicular height, and half the product will be the area. EXAMPLE 1. I What is the area of a triatgk ABC, the base AB being 12f. 3i. and the height BC 8f. 6i.?... | |
 | John Gummere - 1814 - 398 sider
...32.5P. PROBLEM II. To find the area of a triangle when the base and per pendicular height are given. RULE. Multiply the base by. the perpendicular height, and half the product will be the area.* • DEMONSTRATION. A triangle is half a parallelogram of the same base and altitude (41.1.), and therefore... | |
 | Thomas Keith - 1817 - 306 sider
...area of the parallelogram, viz. A cxc D x natural sine of the angle c — the area. PROBLEM IV. Tofind the Area of a Triangle. RULE. Multiply the base by...perpendicular height, and half the product will be the area *. Example 1. If the base of a triangle be 15'4 inches, and the perpendicular 7'8 inches, what is the... | |
 | 1821 - 708 sider
...Multiply the base 30 feet by the perpendicular 15 feet; the product 460 is tlic •. / area in square feet. PROBLEM II. To find the area of a Triangle. RULE. Multiply the base by half the perpendicular height, and the product will be the area required. A a 178 EXAMPLE. Given the... | |
 | John Nicholson - 1825 - 822 sider
...area of a rhombus, whose length is 6 chains, and perpendicular height 5. — 6 5 Ansr. 30 Prol. 2. To find the Area of a Triangle. Rule ] . Multiply...perpendicular height, and half the product will be the area. Rule 2. When the three sides only are given : Add the three sides together, and take half the sum ;... | |
 | Peter Nicholson - 1825 - 1046 sider
...8125 f. 89.375 Л 89 4 6 f. i ii Ans. 89 ft. 4 in. 6 parts. Prob. 2. To find the area of a triangle. Multiply the base by the perpendicular height, and half the product will be the area. Ex. What is the area of a triangle ABC, the base AB being 12f. 3i. and the height CD 8f. 6i. ? By duodecimals.... | |
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To find the Area of a Triangle. Rule ] . Multiply the base by the perpendicular height, and half the product will be the area. 
