 | Charles Vyse - 1785 - 350 sider
...RULE, 3. From Half the Burn of the three Sides fubtnuft each Side feverally ; multiply the Half Sura and the three Remainders continually together, and the Square Root of the laft ProducT. will be the Area 6f the Triangle, that is, * • Tc— 2. *=Half the Sum of the Sides.... | |
 | Charles Vyse - 1806 - 342 sider
...given, to find the Area. RULE. 3. From Half the Sum of the three Sides subtract each Side severally ; multiply the Half Sum and the three Remainders continually together, and the Square Root of the last Produdl will be the Area of the Triangle, that is, ^++l= j = Half the Sum of the Sides'. 2 Then... | |
 | Samuel Webber - 1808 - 466 sider
...the three sides together, and take half the sum ; from the halt. sum subtract each side separately ; multiply the half sum and the three remainders continually together ; and the square root of the last product will be the area of the triangle. • A triangle is half a parallelogram of the same base... | |
 | Peter Nicholson - 1809 - 426 sider
...sum of the three sides, subtract each side severally; multiply the half sum and the three remainders together, and the square root of the product will be the area required. EXAMPLE I. Rcquireth the area of a triangle ABC, whose three sides AB, BC, and CA, are respectively... | |
 | John Gummere - 1817 - 384 sider
...the three sides are given. RULE. From half the sum of the three sides subtract each sifle severally ; multiply the half sum and the three remainders continually together, and the square root of the last product will be the area. * » DEMONSTRATION. Let ABC, Fig. 69, be the triangle. Bisect any two... | |
 | Anthony Nesbit - 1824 - 476 sider
...only of which are given. RULE. From half the sum of the three sides subtract each side severally ; multiply the half sum and the three remainders continually together; and the square root of the last product will be the area of the triangle. Jvofe t. If a triangle be accurately laid down, from... | |
 | John Nicholson - 1825 - 822 sider
...the three sides together, and take half the sum ; from the half sum subtract each side separately; multiply the half sum and the three remainders continually together ; and the square root of the last product will be the area of the triangle. Ex. Required the area of the triangle whose base is... | |
 | Peter Nicholson - 1825 - 1046 sider
...of the three sides, subtract each side severally ¡ multiply the half sum and the three remainders together, and the square root of the product will be the area required. Едг. Requireth the area of a triangle ABC, whose three »ides AB BC, and CA, are respectively 13,... | |
 | Zadock Thompson - 1826 - 176 sider
...given, add these together, and tuke half the sum ; from the half sum subtract each side separately ; multiply the half sum and the three remainders continually together, and the square root of the last product will be the area of the triangle. Examples. 1. How many square feet in a triangle whose... | |
 | Thomas Hornby (land surveyor.) - 1827 - 318 sider
...sides together, and take half the sum; subtract each side from that half sum ; then multiply the said half sum and the three remainders continually together...and the square root of the product will be the area of the triangle. EXAMPLES. 1. — Required the area of the triangular field ABC, whose base AB is 650,... | |
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Multiply the half sum and the three remainders continually together, and the square root of the product will be the area... 
