College Entrance Examination Papers in Plane GeometryCharles E. Merrill Company, 1911 - 178 sider |
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Resultat 1-5 av 27
Side 6
... Subtended by a Side RV3 Triangle 2AV3 R 3R2√3 3A2√3 R2 ( 4x - 3√3 ) 12 Square RV2 1.414R 2A RV2 R2 2R2 442 S2 ( 7-2 ) 4 2A .707R 2R2 4A2 S2 2854 R2 Pentagon RV10-2√2A√5-2√5 | R ( √5 + 1 ) S2 R2√10 + 2√5 5425-2√5 R2 4 40 25 + ...
... Subtended by a Side RV3 Triangle 2AV3 R 3R2√3 3A2√3 R2 ( 4x - 3√3 ) 12 Square RV2 1.414R 2A RV2 R2 2R2 442 S2 ( 7-2 ) 4 2A .707R 2R2 4A2 S2 2854 R2 Pentagon RV10-2√2A√5-2√5 | R ( √5 + 1 ) S2 R2√10 + 2√5 5425-2√5 R2 4 40 25 + ...
Side 16
... subtended by the arc , and the tangent to the arc at one extremity , show that the perpendiculars dropped from the middle point of the arc on the tangent and chord , respectively , are equal . One extremity of the base of a triangle is ...
... subtended by the arc , and the tangent to the arc at one extremity , show that the perpendiculars dropped from the middle point of the arc on the tangent and chord , respectively , are equal . One extremity of the base of a triangle is ...
Side 17
... subtends a right angle at the centre of the circle . State briefly how you might find tional to three given straight lines . a fourth propor- 4. Prove that in any obtuse - angled triangle the square of the side opposite the obtuse angle ...
... subtends a right angle at the centre of the circle . State briefly how you might find tional to three given straight lines . a fourth propor- 4. Prove that in any obtuse - angled triangle the square of the side opposite the obtuse angle ...
Side 18
... subtends an angle of 300 ° at its own centre . Find the area of the window , assuming the length of the perimeter to be 110 feet . JUNE , 1897 Take as many propositions as you can in the time allowed for the examination , attacking ...
... subtends an angle of 300 ° at its own centre . Find the area of the window , assuming the length of the perimeter to be 110 feet . JUNE , 1897 Take as many propositions as you can in the time allowed for the examination , attacking ...
Side 19
... subtended by equal chords . Two equal chords of a certain circle meet on the circum- ference at an angle of 60 ° and intercept an arc 8 feet long . How long an arc does each chord subtend ? 3. Prove that , if a circle be described on ...
... subtended by equal chords . Two equal chords of a certain circle meet on the circum- ference at an angle of 60 ° and intercept an arc 8 feet long . How long an arc does each chord subtend ? 3. Prove that , if a circle be described on ...
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College Entrance Examination Papers in Plane Geometry (Classic Reprint) Charles A. Marsh Ingen forhåndsvisning tilgjengelig - 2017 |
College Entrance Examination Papers in Plane Geometry (Classic Reprint) Charles A. Marsh Ingen forhåndsvisning tilgjengelig - 2017 |
Vanlige uttrykk og setninger
ABCD adjacent angles altitude angle is equal apothem bisector bisects centre circle of radius circum circumference circumscribed circle diameter dihedral angles distance equal angles equal circles equal respectively equal to one-half equilateral triangle EXAMINATIONS IN PLANE external segment feet Find the area Find the length Find the locus fixed point GEOMETRY FOR ADMISSION given circle given line given point given straight line homologous sides hypotenuse included angle inscribed circle intercepted arcs interior angles isosceles triangle joining the middle JUNE lines drawn mean proportional measured by one-half middle points non-parallel sides number of sides opposite side parallel lines parallelogram PLANE GEOMETRY point of contact point of intersection quadrilateral radii ratio rectangle regular hexagon regular polygon rhombus right angles right triangle SEPTEMBER Show similar polygons similar triangles solid geometry subtends theorem third side three sides trapezoid triangle ABC triangle divides triangles are equal triangles are similar vertex whole secant zoid
Populære avsnitt
Side 96 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles.
Side 52 - ... meeting the plane at unequal distances from the foot of the perpendicular the more remote is the greater.
Side 84 - Two triangles which have an angle of one equal to the supplement of an angle of the other are to each other as the products of the sides including the supplementary angles.
Side 16 - In any triangle, the square of the side opposite an acute angle is equal to the sum of the squares of the other two sides diminished by twice the product of one of those sides and the projection of the other upon that side.
Side 95 - The straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to half of it.
Side 17 - In any obtuse triangle, the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, increased by twice the product of one of these sides and the projection of the other side upon it.
Side 59 - Construct a circle having its center in a given line and passing through two given points. 3. The bisector of the angle of a triangle divides the opposite side into segments which are proportional to the two other sides.
Side 172 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.
Side 135 - If two triangles have two sides of one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side of the first is greater than the third side of the second.
Side 60 - The area of a circle is equal to one-half the product of its circumference and radius.