The first six books of the Elements of Euclid, and propositions i.-xxi. of book xi1885 |
Inni boken
Side 99
... equal to twice the angle of an equilateral triangle , AB2 BC2 + CA2 + BC ... perpendicular on the hypotenuse AC ; Prove AB . DC BD . BC . = - 4. If a line AB be divided in C so that AC2 = 2CB2 ; prove that AB2 + BC2 = 2AB . AC . 5. If AB be ...
... equal to twice the angle of an equilateral triangle , AB2 BC2 + CA2 + BC ... perpendicular on the hypotenuse AC ; Prove AB . DC BD . BC . = - 4. If a line AB be divided in C so that AC2 = 2CB2 ; prove that AB2 + BC2 = 2AB . AC . 5. If AB be ...
Side 143
... equal to the rectangle contained by their diameters . PROP . XXXIII ... diameter describe a circle it will be the circle required . Dem . The circle ... triangle , being given base , vertical_angle , and any of the following data : -1 ...
... equal to the rectangle contained by their diameters . PROP . XXXIII ... diameter describe a circle it will be the circle required . Dem . The circle ... triangle , being given base , vertical_angle , and any of the following data : -1 ...
Side 146
... diameter FG . Then by 3 , the rectangle FE . EG is equal to the rectangle AE ... contained by its segments is equal to the difference between the ' square of ... triangle , the rectangle contained by two sides is equal to the rectangle ...
... diameter FG . Then by 3 , the rectangle FE . EG is equal to the rectangle AE ... contained by its segments is equal to the difference between the ' square of ... triangle , the rectangle contained by two sides is equal to the rectangle ...
Side 147
... equal to the rectangle contained by the radius and the chord of twice the supplement . 3. If the base of a triangle ... diameter which is perpendicular to AB , and draw the chords CF , BG parallel to DE . Now it is evident that the difference ...
... equal to the rectangle contained by the radius and the chord of twice the supplement . 3. If the base of a triangle ... diameter which is perpendicular to AB , and draw the chords CF , BG parallel to DE . Now it is evident that the difference ...
Side 153
... equal to the square on the diameter . 2. If a chord of a given circle subtend a right angle at a fixed point , the rectangle ... triangle formed by it and two fixed tangents to the circle shall be - 1 , a ... perpendicular from any point in the ...
... equal to the square on the diameter . 2. If a chord of a given circle subtend a right angle at a fixed point , the rectangle ... triangle formed by it and two fixed tangents to the circle shall be - 1 , a ... perpendicular from any point in the ...
Vanlige uttrykk og setninger
ABCD AC is equal AD² adjacent angles altitude angle ABC angle ACB angle BAC angular points Axiom bisector bisects centre chord circles touch circumference circumscribed circle collinear concurrent lines const coplanar cyclic quadrilateral Dem.-Let diagonals diameter divided draw equal angles equal to AC equiangular equilateral triangle escribed circles Euclid Exercises exterior angle Geometry given circle given line given point greater Hence the angle hypotenuse inscribed isosceles less line AC line joining locus manner meet middle points multiple nine-points circle opposite sides parallel parallelogram parallelopiped perpendicular plane points of intersection prism PROP Proposition prove radii radius rectangle contained rectilineal figure regular polygon respectively equal right angles right line segments semicircle sides AC similar square on AC tangent theorem triangle ABC vertex vertical angle
Populære avsnitt
Side 295 - Thus the proposition, that the sum of the three angles of a triangle is equal to two right angles, (Euc.
Side 182 - When of the equimultiples of four magnitudes (taken as in the fifth definition) the multiple of the first is greater than that of the second, but the multiple of the third is not greater than the multiple of the fourth ; then the first is said to have to the second a greater ratio than the third magnitude has to the fourth...
Side 9 - LET it be granted that a straight line may be drawn from any one point to any other point.
Side 102 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square on the other part.
Side 122 - The diameter is the greatest straight line in a circle; and, of all others, that which is nearer to the centre is always greater than one more remote; and the greater is nearer to the centre than the less. Let ABCD be a circle, of which...
Side 226 - If from any angle of a triangle, a straight line be drawn perpendicular to the base ; the rectangle contained by the sides of the triangle is equal to the rectangle contained by the perpendicular and the diameter of the circle described about the triangle.
Side 29 - Again ; the mathematical postulate, that " things which are equal to the same are equal to one another," is similar to the form of the syllogism in logic, which unites things agreeing in the middle term.
Side 63 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Side 126 - The diagonals of a quadrilateral intersect at right angles. Prove that the sum of the squares on one pair of opposite sides is equal to the sum of the squares on the other pair.
Side 194 - If there be any number of proportionals, as one antecedent is to its consequent, so is the sum of all the antecedents to the sum of all the consequents.