First Lessons in Algebra: Embracing the Elements of the ScienceA.S. Barnes, 1841 - 252 sider |
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First Lessons in Algebra: Embracing the Elements of the Science Charles Davies Uten tilgangsbegrensning - 1840 |
First Lessons in Algebra: Embracing the Elements of the Science Charles Davies Uten tilgangsbegrensning - 1839 |
First Lessons in Algebra: Embracing the Elements of the Science Charles Davies Uten tilgangsbegrensning - 1839 |
Vanlige uttrykk og setninger
ac ac algebraic quantities arithmetical means arithmetical progression binomial Binomial Theorem called cents common denominator common difference complete equation completing the square composed contain contrary sign cube decimal denotes dividend division divisor dollars double product enunciation equation gives equation involving EXAMPLES exponent extracting the square fifth power figure find a number Find the square Find the sum Find the values following RULE four quantities fourth power geometrical progression Give the rule given number greater greyhound Hence last term leaps least common multiple minus mixed quantity monomial Multiply negative number of terms obtain ounces of silver perfect square polynomial question quotient ratio Reduce remainder second degree second power second term simplest form square root Substituting this value take the equation tens three terms tion transposing trinomial twice the product unknown quantity values of x Verification whence yards
Populære avsnitt
Side 230 - To express that the ratio of A to B is equal to the ratio of C to D, we write the quantities thus : A : B : : C : D ; and read, A is to B as C to D.
Side 214 - A merchant bought cloth for which he paid £33 15s, which he sold again at £2 8s per piece, and gained by the bargain as much as one piece cost him : how many pieces did he buy 1 Ans.
Side 175 - Since the square of a binomial is equal to the square of the first term, plus twice the product of the first term by the second, plus the square of the second...
Side 155 - Obtain the exponent of each literal factor in the quotient by subtracting the exponent of each letter in the divisor from the exponent of the same letter in the dividend; Determine the sign of the result by the rule that like signs give plus, and unlike signs give minus.
Side 233 - AC and by clearing the equation of fractions we have BO=AD; that is, Of four proportional quantities, the product of the two extremes is equal to the product of the two means.
Side 138 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 35 - The square of the sum of two quantities is equal to the square of the first, plus twice the product of the first and second, plus the square of the second.
Side 79 - Ibs., his head weighed as much as his tail and half his body, and his body weighed as much as his head and t.ail together : what was the weight of the fish ? Let 2x = the weight of the body, in pounds.
Side 197 - That the sum of the two roots is equal to the coefficient of x in the second term, taken with a contrary sign. 4th. That the product of the roots is equal to the known term in the second member, taken with a contrary sign. EXAMPLES. 1.
Side 45 - ... the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend.