 | 1801 - 446 sider
...•**" r — I L, I — Z,, a • ~L7r +K / rriXr+a 37 ' 7 r ff L,r 4ad ' • t — a _ L, l—L,a 5. Divide the dividend by the divisor, and the quotient will be the term sought. NOTE. When the first term of the series is equal to the ratio, the indices must begin... | |
 | Paul Deighan - 1804 - 504 sider
...and multiply it by the index of the given power for a divifor, 4. Divide the dividend by the divifor, and the quotient will be the next term of the root. 5. Involve the whole root, and fubtraft and divide as before ; and fo on till the whole is fini (lied. EXAMPLES. t. Required the cube... | |
 | Nicolas Pike - 1808 - 470 sider
...the first term, and place it in the quo.pent. 2. Subtract the power, and bring down the second terra for a dividend. 3. Involve the root, last found, to...subtract and divide as before ; and so on till the whole be finished. j. Required the square root of a* — 2a3r— 2<z3r+3a2/-» — 5 a*— 2a 3r+3asra—... | |
 | Samuel Webber - 1808 - 466 sider
...bring down the second term for a dividend. 3. Involve the root, already found, to the next inferior power, and multiply it by the index of the given power...the next term of the root. 5. Involve the whole root to the given power, and subtract it from, the given quantity ; then bring down the next term, and proceed... | |
 | Samuel Webber - 1812 - 260 sider
...ars < ' r n V — IXs+a — Z,a L,r s — a 4 asl < r K— T n LJ-L,a Z,5 — a — Z,A- — / \ 5. Divide the dividend by the divisor, and the quotient will be the term sought. N0TE. When the first term of the series is equal to the ratio, the indices must begin... | |
 | Charles Butler - 1814 - 540 sider
...found to the next lower power, and multiply it by the index of the given power, for a divisor. IV. Divide the dividend by the divisor, and the quotient will be the next term of the root. V. Involve the whole root, subtract, divide, and proceed as before, until the whole is finished. EXAMPLES.... | |
 | Charles Butler - 1814 - 540 sider
...for a divisor ; but if less, mark the greater extreme. and the marked ones together for a divisor; divide the dividend by the divisor, and the quotient will be the answer in the same denomination the second term was brought into ». EXAMPLES. l. If 6 men spend 154... | |
 | Zadock Thompson - 1826 - 176 sider
...the first term to a power whose index is 1 less than the number of terms multiplied for a divisor ; divide the dividend by the divisor, and the quotient will be the term sought. NOTE. — When the first term of the series is equal to the ratio, the indices must begin... | |
 | 1826 - 418 sider
...dividend ; and subtract the former part of this product from the given radius, for a divisor. Then divide the dividend by the divisor, and the quotient will be the other radius. a, = .600 Focal length, = 12 ~iv~n~ viif from 10 7-2 = first product] take 7.3 Given... | |
 | 1826 - 428 sider
...dividend ; and subtract the former part of this product from the given radius, for a divisor. Then divide the dividend by the divisor, and the quotient will be the other radius. Example. — The index of a piece of flint-glass is 1-600, and one of its curvatures... | |
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... 4. Divide the dividend by the divisor, and the quotient will be the next term of the root. 5. Involve the whole root... 
