Elementary text book for young surveyors and levellersSimpkin, Marshall & Company, 1856 - 185 sider |
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Side vii
... Rule are such , that the pupil , who carefully studies them , cannot help becoming master of the subject - he will certainly have nothing to unlearn , should he afterwards follow it professionally . It seems almost unnecessary to offer ...
... Rule are such , that the pupil , who carefully studies them , cannot help becoming master of the subject - he will certainly have nothing to unlearn , should he afterwards follow it professionally . It seems almost unnecessary to offer ...
Side 21
... Rule . Divide the square chains by 10 , to bring them to acres , and then multiply by 4 and 40 as before . EXAMPLE 1. Let the area of a field equal 8.2500 square chains ( that is 8 square chains and 2500 square links ) . Required the ...
... Rule . Divide the square chains by 10 , to bring them to acres , and then multiply by 4 and 40 as before . EXAMPLE 1. Let the area of a field equal 8.2500 square chains ( that is 8 square chains and 2500 square links ) . Required the ...
Side 22
... Rule . Multiply the base by the height . EXAMPLE 1. What is the area of a triangular field , whose base is 5 chains 50 links , and height 3 chains 20 links ? 5.50 x 3.20 2 8.8000 sq . chs . , A. R. P. and 8.8000 sq . chs . 0. 3. 20 ...
... Rule . Multiply the base by the height . EXAMPLE 1. What is the area of a triangular field , whose base is 5 chains 50 links , and height 3 chains 20 links ? 5.50 x 3.20 2 8.8000 sq . chs . , A. R. P. and 8.8000 sq . chs . 0. 3. 20 ...
Side 23
... Rule . Take half the sum of the three sides , subtract each side severally from this sum ; then multiply this and the three remainders together , and take the square root for the area . EXAMPLE 1. What is the area of a triangle , whose ...
... Rule . Take half the sum of the three sides , subtract each side severally from this sum ; then multiply this and the three remainders together , and take the square root for the area . EXAMPLE 1. What is the area of a triangle , whose ...
Side 24
... Rule . Multiply half the sum of the two parallel sides by the distance between them . EXAMPLE 1. In a trapezoid , whose parallel sides are 7 chains 25 links and 8 chains 63 links , the distance being 11 chains 65 links , how many acres ...
... Rule . Multiply half the sum of the two parallel sides by the distance between them . EXAMPLE 1. In a trapezoid , whose parallel sides are 7 chains 25 links and 8 chains 63 links , the distance being 11 chains 65 links , how many acres ...
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Elementary Text Book for Young Surveyors and Levellers with Copious Field ... Henry James Castle Ingen forhåndsvisning tilgjengelig - 2019 |
Elementary Text Book for Young Surveyors and Levellers With Copious Field ... Henry James Castle Ingen forhåndsvisning tilgjengelig - 2019 |
Vanlige uttrykk og setninger
2nd gate A. R. P. Answer angle of bearing angle of elevation base line bisect broad arrow centre chain surveying chains 50 links CHAP CHECK ANGLES check line circle circumferentor clamp corner correct cross customary determined diagonal DIAGRAM distance ditch divided draw equal Euclid EXAMPLE fence field book field notes flag gate post given angle given line given point half degrees hedge height horizontal inch interior angles intersection join Lancashire length line AC long scale mark meridian line motion needle number of degrees object observation offsets perpendicular placed plot pond protractor Required the true right angles right-angled triangle river road roods round screws similar triangles spirit level square chains square feet statute acres statute measure taken telescope theodolite top of bank trapezium triangle ABC true bearing true north vertical whole instrument width Wiltshire Wood
Populære avsnitt
Side 111 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 160 - LEVELLING is the art of representing the inequalities of the earth's surface, and of determining the relative heights of any number of points above or below a line, equidistant, at every point, from the centre of the earth.
Side 17 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.
Side 8 - To describe a square upon a given straight line. Let AB be the given straight line : it is required to describe a square upon AB.
Side 102 - The existence of parallax is determined by moving the eye about, when looking through the telescope, observing whether the cross wires change their position, and are flittering and undefined. To correct this error, first adjust the eye-piece, by means of the moveable eye-piece tube, till you can perceive the cross wire clearly defined, and sharply marked against any white object.
Side 23 - C will be found 9, the square root on D. For the square root of 144 : Set 1 on C to 10 on D ; then against 144 on C will be found the square root 12 on D. 42. To find the area of a board or plank : The rule is, to multiply the length by the breadth, the product will be the area ; therefore, by the sliding rule, Set 12 on B against the breadth in inches on A ; then...
Side 16 - E, the adjacent angles CEA, AED; these angles are together equal to two right angles. (i. 13.) Again, because the straight line DE makes with AB...
Side 28 - To find the area of a circle. Rule — Multiply the square of the diameter by .7854; or the square of the radius by 3.1416; or the square of the circumference by .07958. Find the area of a piston 20 in. in diam. Answer— 20!
Side 8 - To draw a straight line at right angles to a given straight line, from a given point in the same. Let AB be the given straight line, and C the given point in it : it is required to draw from the point C a straight line at right angles to AB.
Side 23 - To find the Area of a Triangle when the Three Sides are given. Rule. — From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of the product.