Elementary text book for young surveyors and levellersSimpkin, Marshall & Company, 1856 - 185 sider |
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Resultat 1-5 av 14
Side 5
... joining the extremities of the arc . A segment is the space included between the chord and the arc . The sector of a circle , is the space included between two radii , and the arc ; therefore the sector of a right angle is a quadrant ...
... joining the extremities of the arc . A segment is the space included between the chord and the arc . The sector of a circle , is the space included between two radii , and the arc ; therefore the sector of a right angle is a quadrant ...
Side 6
... join AC and BC . ABC is the equilateral tri- angle required . A B 2. From a point , within a given line , to erect a perpendicular . Let AB be the given line , and C be the given point . From C , as a centre , take any distance , CA ...
... join AC and BC . ABC is the equilateral tri- angle required . A B 2. From a point , within a given line , to erect a perpendicular . Let AB be the given line , and C be the given point . From C , as a centre , take any distance , CA ...
Side 7
... Join the points of intersection with the given point A , and the lines will be perpendicular to , or making the ... join CD , and pro- duce to E. Join EA . EA will be the perpendicular required . D B 4. To bisect a given straight line ...
... Join the points of intersection with the given point A , and the lines will be perpendicular to , or making the ... join CD , and pro- duce to E. Join EA . EA will be the perpendicular required . D B 4. To bisect a given straight line ...
Side 8
... join CH . CH is the perpendicular required . 6. To bisect a given angle . Let ABC be the given angle ; take any point D in AB , and from B , as a centre , at the dis- tance BD , describe the circle DGE ; join DE , and bisect it in F ; join ...
... join CH . CH is the perpendicular required . 6. To bisect a given angle . Let ABC be the given angle ; take any point D in AB , and from B , as a centre , at the dis- tance BD , describe the circle DGE ; join DE , and bisect it in F ; join ...
Side 9
... join CD , and at the point C make the angle DCE equal to the angle ADC ; produce EC to F. EF shall be parallel to AB . C 18 9. To divide a given line , AB , into GEOMETRICAL PROBLEMS . sides only can be obtained when the inclination of ...
... join CD , and at the point C make the angle DCE equal to the angle ADC ; produce EC to F. EF shall be parallel to AB . C 18 9. To divide a given line , AB , into GEOMETRICAL PROBLEMS . sides only can be obtained when the inclination of ...
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Elementary Text Book for Young Surveyors and Levellers with Copious Field ... Henry James Castle Ingen forhåndsvisning tilgjengelig - 2019 |
Elementary Text Book for Young Surveyors and Levellers With Copious Field ... Henry James Castle Ingen forhåndsvisning tilgjengelig - 2019 |
Vanlige uttrykk og setninger
50 links A. R. P. Answer acres angle of bearing Answer base line bearing beginning bring carefully centre chains circle corner correct cross customary describe determined difference direction distance ditch divided division draw east edge English equal EXAMPLE fall feet fence field fixed flag gate given given line graduated half hedge height horizontal instrument intersection join length lower mark means measured meridian minutes motion needle object observation obtained offset parallel perches perpendicular placed plate plot pond position practice PROBLEM produced right angles river road roods round Rule runs scale side square square feet station straight surveying taken taking theodolite third triangle turn upper variation vernier vertical whole width Wood yards
Populære avsnitt
Side 111 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 160 - LEVELLING is the art of representing the inequalities of the earth's surface, and of determining the relative heights of any number of points above or below a line, equidistant, at every point, from the centre of the earth.
Side 17 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.
Side 8 - To describe a square upon a given straight line. Let AB be the given straight line : it is required to describe a square upon AB.
Side 102 - The existence of parallax is determined by moving the eye about, when looking through the telescope, observing whether the cross wires change their position, and are flittering and undefined. To correct this error, first adjust the eye-piece, by means of the moveable eye-piece tube, till you can perceive the cross wire clearly defined, and sharply marked against any white object.
Side 23 - C will be found 9, the square root on D. For the square root of 144 : Set 1 on C to 10 on D ; then against 144 on C will be found the square root 12 on D. 42. To find the area of a board or plank : The rule is, to multiply the length by the breadth, the product will be the area ; therefore, by the sliding rule, Set 12 on B against the breadth in inches on A ; then...
Side 16 - E, the adjacent angles CEA, AED; these angles are together equal to two right angles. (i. 13.) Again, because the straight line DE makes with AB...
Side 28 - To find the area of a circle. Rule — Multiply the square of the diameter by .7854; or the square of the radius by 3.1416; or the square of the circumference by .07958. Find the area of a piston 20 in. in diam. Answer— 20!
Side 8 - To draw a straight line at right angles to a given straight line, from a given point in the same. Let AB be the given straight line, and C the given point in it : it is required to draw from the point C a straight line at right angles to AB.
Side 23 - To find the Area of a Triangle when the Three Sides are given. Rule. — From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of the product.