...tens plus the unite, or 2 a + b ; this multiplied by 7 or 6, reproduces 609 = 2 ab + 62, or double the product of the tens by the units, plus the square of the units. This being subtracted leaves no remainder, and the operation shows, that 47 is the square root of 2209....

...the tens plus the units, or 2 a + b ; this multiplied by 7 or b, reproduces 609 = 2a6 + 6s, or double the product of the tens by the units, plus the square of the units. This being subtracted leaves no remainder, and the operation •hows, that 47 is the square root of...

...add these products, and we have, for the square, the number 2916, which, as we see, is composed of the square of the tens, plus twice the product of...the tens by the units, plus the square of the units of the number 54. 134. What we have, observed being an immediate consequence of the rules of multiplication,...

...62=2209. Thus the square of a number, consisting of units and tens, is composed of three parts, viz. the square of the tens, plus twice the product of the tens multiplied by the units, plus the square of the units. Thus in 2209, the square of 47, we have The...

...appears that the square of a number consisting of tens and units is made up of the square of the units, plus twice the product of the tens, by the units, plus the square of the tens. See this exhibited in figure F. As 10X 10=100, the square of the tens can never make a part of...

...appears that the square of a number consisting of tens and units is made up of the square of the units, plus twice the product of the tens, by the units, plus the square of the tens. See this exhibited in figure F. As 10X 10=100, the square of the tens cau never make a part of...

...64 and (a+i)3= (64)3 Which proves that the square of a number composed of tens and units contains, the square of the tens plus twice the product of the tens by the units, plus the square of the units. 117. If now, we make the units 1, 2, 3, 4, &c., tens, by annexing to each figure a cipher, we shall...

...the units, we shall have, for the square of a + b, a3 + 2ab + b ; that is, the square of the tens, twice the product of the tens by the units, plus the square of the units. Let a = 8, and 6 = 5: then, since a represents the tens, and b the units, a + b becomes 80 + 5 = 85...

...units. Denoting the tens by a, and the units by b, we have (Art. 198), Whence it follows, that the cube of a number composed of tens and units, is equal to the cube of the tens, plus three times the product of the square of the tens by the units, plus three times...

...shall have a+b =64, and Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units. 94. If, now, we make the units 1,2, 3, 4, &c, tens, or units of the second order, by annexing to each...