Elements of GeometryHilliard and Metcalf, 1825 - 224 sider |
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Side 22
... centre . The circle is the space terminated by this curved line * . 91. Every straight line CA , CE , CD ( fig . 46 ) , & c . drawn from the centre to the circumference is called a radius or semi- diameter , and every straight line , as ...
... centre . The circle is the space terminated by this curved line * . 91. Every straight line CA , CE , CD ( fig . 46 ) , & c . drawn from the centre to the circumference is called a radius or semi- diameter , and every straight line , as ...
Side 23
... centre , which is contrary to the definition of a circle . THEOREM . 99. Every chord is less than the diameter . Demonstration . If the radii CA , CD ( fig . 49 ) , be drawn from Fig . 49 . the centre to the extremities of the chord AD ...
... centre , which is contrary to the definition of a circle . THEOREM . 99. Every chord is less than the diameter . Demonstration . If the radii CA , CD ( fig . 49 ) , be drawn from Fig . 49 . the centre to the extremities of the chord AD ...
Side 25
... centre , and the middle of the arc subtended by that chord . For this perpendicular is the same as that let fall from the centre upon the same chord , since they both pass through the middle of the chord ( 51 ) . THEOREM . 107. The ...
... centre , and the middle of the arc subtended by that chord . For this perpendicular is the same as that let fall from the centre upon the same chord , since they both pass through the middle of the chord ( 51 ) . THEOREM . 107. The ...
Side 26
... centre O with the radius OB , will pass through the three points A , B , C. It is thus proved , that the circumference of a circle may be made to pass through any three given points , which are not in the same straight line ; it remains ...
... centre O with the radius OB , will pass through the three points A , B , C. It is thus proved , that the circumference of a circle may be made to pass through any three given points , which are not in the same straight line ; it remains ...
Side 27
... centre , and of two unequal chords the less is at the greater distance from the centre . Demonstration 1. Let the chord AB = DE ( fig . 53 ) . Bisect Fig.53 . these chords by the perpendicular CF , CG , and draw the radii CA , CD . The ...
... centre , and of two unequal chords the less is at the greater distance from the centre . Demonstration 1. Let the chord AB = DE ( fig . 53 ) . Bisect Fig.53 . these chords by the perpendicular CF , CG , and draw the radii CA , CD . The ...
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Vanlige uttrykk og setninger
ABC fig adjacent angles altitude angle ACB angle BAD angles equal base ABCD bisect centre chord circ circular sector circumference circumscribed common cone consequently construction convex surface Corollary cube cylinder Demonstration diagonals diameter draw drawn equal and parallel equiangular equilateral equivalent faces figure four right angles frustum Geom gles greater hence homologous sides hypothenuse inclination inscribed circle intersection isosceles join less let fall line AC manner mean proportional measure the half meet multiplied number of sides oblique lines opposite parallelogram parallelopiped perimeter perpendicular plane MN polyedron prism proposition quadrilateral radii radius ratio rectangle regular polygon right angles right-angled triangle Scholium segment semicircumference side BC similar solid angle sphere spherical polygons spherical triangle square described straight line tangent THEOREM three plane angles triangle ABC triangular prism triangular pyramids vertex vertices whence
Populære avsnitt
Side 65 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.
Side 21 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Side ii - Co. of the said district, have deposited in this office the title of a book, the right whereof they claim as proprietors, in the words following, to wit : " Tadeuskund, the Last King of the Lenape. An Historical Tale." In conformity to the Act of the Congress of the United States...
Side 63 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Side 22 - CIRCLE is a plane figure bounded by a curved line, all the points of which are equally distant from a point within called the centre; as the figure ADB E.
Side ii - States entitled an act for the encouragement of learning hy securing the copies of maps, charts and books to the author., and proprietors of such copies during the times therein mentioned, and also to an act entitled an act supplementary to an act, entitled an act for the encouragement of learning by securing the copies of maps, charts and books to the authors and proprietors of such copies during the times therein mentioned and extending the benefits thereof to the arts of designing, engraving and...
Side 80 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Side 164 - If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects.
Side 24 - In the same circle, or in equal circles, equal arcs are subtended by equal chords ; and, conversely, equal chords subtend equal arcs.
Side 153 - XVII.) ; hence two similar pyramids are to each other as the cubes of their homologous sides.