Key to Exercises in EuclidMacmillan and Company, 1880 - 114 sider |
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Resultat 1-5 av 39
Side 1
... construction . The angle BAD is equal to half the angle ABC , by hypothesis . Therefore the angle DBA is equal to the angle BAD . Therefore BD is equal to AD by I. 6 . 6. It is shewn in the demonstration of I. 5 , that the angle BCF is ...
... construction . The angle BAD is equal to half the angle ABC , by hypothesis . Therefore the angle DBA is equal to the angle BAD . Therefore BD is equal to AD by I. 6 . 6. It is shewn in the demonstration of I. 5 , that the angle BCF is ...
Side 5
... construction fails . We must then draw a straight line KL parallel to CD and EF , and midway between them : the intersection of this straight line with AB , produced if necessary , will be the required point . But if KL is parallel to ...
... construction fails . We must then draw a straight line KL parallel to CD and EF , and midway between them : the intersection of this straight line with AB , produced if necessary , will be the required point . But if KL is parallel to ...
Side 7
... construction ; the angle EDA is equal to the angle DAF , and the angle FDA to the angle DAE , by I. 29 ; so that the angle EDA is equal to the angle FDA ; hence the two triangles are equal in all respects by I. 26. Thus DE is equal to ...
... construction ; the angle EDA is equal to the angle DAF , and the angle FDA to the angle DAE , by I. 29 ; so that the angle EDA is equal to the angle FDA ; hence the two triangles are equal in all respects by I. 26. Thus DE is equal to ...
Side 8
... construction . The angle ACE is equal to the angle BCD , each being one - third of two right angles , by I. 32 ; to each of these add the angle ACB : therefore the whole angle ACD is equal to the whole angle BCE . Thus in the two ...
... construction . The angle ACE is equal to the angle BCD , each being one - third of two right angles , by I. 32 ; to each of these add the angle ACB : therefore the whole angle ACD is equal to the whole angle BCE . Thus in the two ...
Side 10
... construction together equal to three halves of a right angle , therefore the angle ACB is half a right angle by I. 32. Thus the half of the angle ACB is a fourth of a right angle , and is therefore equal to one third of each of the ...
... construction together equal to three halves of a right angle , therefore the angle ACB is half a right angle by I. 32. Thus the half of the angle ACB is a fourth of a right angle , and is therefore equal to one third of each of the ...
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ABCD AC and BD AC is equal angle ABC angle ACB angle BAC angle CAB bisects the angle Cambridge centre chord circle described circumference Crown 8vo describe a circle diameter draw a straight Edition equal to BC equal to four equal to half equal to twice equiangular Euclid Exercise 176 Extra fcap fcap fore given circle given point given straight line greater half a right half the angle Hence Let ABC meeting BC middle point Owens College parallel to BC parallelogram perpendicular plane Professor quadrilateral radius equal rectangle rhombus right angles segment shewn side BC square on BC straight line parallel suppose tangent touch the circle triangle ABC twice the angle twice the rectangle twice the squares
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