Key to Exercises in EuclidMacmillan and Company, 1880 - 114 sider |
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Side 2
... perpendicular to the given straight line AB , and at unequal dis- tances from that straight line . 14. Let AB be the given straight line , C and D the two given points . From D draw DE perpendicular to AB , and produce DE through E to a ...
... perpendicular to the given straight line AB , and at unequal dis- tances from that straight line . 14. Let AB be the given straight line , C and D the two given points . From D draw DE perpendicular to AB , and produce DE through E to a ...
Side 3
... perpendicular , then any point in AB may be taken for the point G. 15. Let the angle BAC be bisected by AD , and the angle BAG by AE : the angle DAE shall be a right angle . Since the angle BAD is half the angle BAC , and the angle BAE ...
... perpendicular , then any point in AB may be taken for the point G. 15. Let the angle BAC be bisected by AD , and the angle BAG by AE : the angle DAE shall be a right angle . Since the angle BAD is half the angle BAC , and the angle BAE ...
Side 5
... perpendicular to the side AB , and DF perpendicular to the side AC . Then in the triangles DAE and DAF , the side DA is common ; the angle DAE is equal to the angle DAF , by hypothesis ; and the right angles DEA and DFA are equal ...
... perpendicular to the side AB , and DF perpendicular to the side AC . Then in the triangles DAE and DAF , the side DA is common ; the angle DAE is equal to the angle DAF , by hypothesis ; and the right angles DEA and DFA are equal ...
Side 7
... perpendicular to AC . 43. Bisect the angle ABC by a straight line , meeting AC at E ; through E draw a straight line parallel to BC , meeting AB at D. Then will BD , DE , EC be all equal . For the angle DEB is equal to the angle EBC ...
... perpendicular to AC . 43. Bisect the angle ABC by a straight line , meeting AC at E ; through E draw a straight line parallel to BC , meeting AB at D. Then will BD , DE , EC be all equal . For the angle DEB is equal to the angle EBC ...
Side 8
... perpendicular to AC meeting AC at D , and from C draw a perpendicular to AB meeting it at E. Then each of the angles CBD , BCE will be equal to half the angle A. Bisect the angle A by a straight line meeting the base BC at F. Then the ...
... perpendicular to AC meeting AC at D , and from C draw a perpendicular to AB meeting it at E. Then each of the angles CBD , BCE will be equal to half the angle A. Bisect the angle A by a straight line meeting the base BC at F. Then the ...
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ABCD AC and BD AC is equal angle ABC angle ACB angle BAC angle CAB bisects the angle Cambridge centre chord circle described circumference Crown 8vo describe a circle diameter draw a straight Edition equal to BC equal to four equal to half equal to twice equiangular Euclid Exercise 176 Extra fcap fcap fore given circle given point given straight line greater half a right half the angle Hence Let ABC meeting BC middle point Owens College parallel to BC parallelogram perpendicular plane Professor quadrilateral radius equal rectangle rhombus right angles segment shewn side BC square on BC straight line parallel suppose tangent touch the circle triangle ABC twice the angle twice the rectangle twice the squares
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