## The Elements of Euclid, containing the first six books, with a selection of geometrical problems. To which is added the parts of the eleventh and twelfth books which are usually read at the universities. By J. Martin |

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Side 9

To describe an equilateral triangle upon a given finite straight line . Let AB be the

To describe an equilateral triangle upon a given finite straight line . Let AB be the

**given straight line**. It is required to describe an equilateral triangle upon AB . O Ө B Construction . From the centre A , at the distance AB ... Side 9

To describe an equilateral triangle upon a given finite straight line . Let AB be the

To describe an equilateral triangle upon a given finite straight line . Let AB be the

**given straight line**. It is required to describe an equilateral triangle upon AB . O Construction . From the centre A , at the distance AB , describe ... Side 10

Let A be the given point , and BC the

Let A be the given point , and BC the

**given straight line**. It is required to draw , from the point A , a straight line equal to BC . K C B Construction . From the point A to B draw the straight line AB ( Post . Side 11

Let AB and C be the two

Let AB and C be the two

**given straight lines**, of which AB is the greater . It is required to cut off from AB the greater , a part equal to C the less . D F Construction . From the point A draw the straight line AD equal to C ( I. 2 ) ... Side 19

Let BAC be the

Let BAC be the

**given**rectilineal angle . It is required to bisect it . Construction . ... Then the**straight line**AF shall bisect the angle BAC , Proof . ... To bisect a**given**finite**straight line**, that is , to divide ...### Hva folk mener - Skriv en omtale

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The Elements of Euclid, Containing the First Six Books, with a Selection of ... Euclides Ingen forhåndsvisning tilgjengelig - 2016 |

### Vanlige uttrykk og setninger

ABCD AC is equal alternate angle ABC angle ACB angle BAC base base BC bisected centre circle ABC circumference common compounded constr Construction Demonstration describe diameter divided double draw equal angles equiangular equimultiples exterior angle extremities fall fore four fourth given point given straight line greater half inscribed interior join less Let ABC likewise magnitudes manner meet multiple opposite angle parallel parallelogram pass perpendicular plane polygon produced Proof proportionals proved Q.E.D. PROPOSITION ratio reason rectangle contained rectilineal figure remaining angle right angles segment shown sides similar square square on AC straight line BC taken third touches the circle triangle ABC unequal wherefore whole

### Populære avsnitt

Side 1 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.

Side 6 - If a straight line meets two straight lines, so as to make the two interior angles on the same side of it taken together less than two right angles...

Side 232 - If two triangles, which have two sides of the one proportional to two sides of the other, be joined at one angle, so as to have their homologous sides parallel to one another, the remaining sides shall be in a straight line. Let...

Side 112 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.

Side 209 - ... triangles which have one angle in the one equal to one angle in the other, and their sides about the equal angles reciprocally proportional, are equal to one another.

Side 269 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.

Side 199 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Side 23 - If two triangles have two angles of the one equal to two angles of the other, each to each, and also one side of the one equal to the corresponding side of the other, the triangles are congruent.

Side 63 - If a straight line be divided into two equal, and also into two unequal parts, the squares on the two unequal parts are together double of the square on half the line and of the square on the line between the points of section. Let the straight line AB be divided into two equal parts...

Side 32 - ... twice as many right angles as the figure has sides ; therefore all the angles of the figure together with four right angles, are equal to twice as many right angles as the figure has sides.