## The Elements of Euclid, containing the first six books, with a selection of geometrical problems. To which is added the parts of the eleventh and twelfth books which are usually read at the universities. By J. Martin |

### Inni boken

Resultat 1-5 av 38

Side 64

EVERY right - angled parallelogram is called a

contained by any two of the straight lines which contain one of the right angles . 2

. In every parallelogram , any of the parallelograms about a diameter , together

with ...

EVERY right - angled parallelogram is called a

**rectangle**, and is said to becontained by any two of the straight lines which contain one of the right angles . 2

. In every parallelogram , any of the parallelograms about a diameter , together

with ...

Side 65

... EL , CH parallel to BG , meeting GH in K , L , H. Demonstration . Then the

and BC , for it is contained by GB , BC , and GB is equal to A ; and the

...

... EL , CH parallel to BG , meeting GH in K , L , H. Demonstration . Then the

**rectangle**BH is equal to the**rectangles**BK , DL , EH ; and 1. BH is contained by Aand BC , for it is contained by GB , BC , and GB is equal to A ; and the

**rectangle**2...

Side 66

Then the

, shall be equal to the square on AB . A D F E Construction . Upon AB describe

the square ADEB ( I. 46 ) , and through C draw CF parallel to AD or BE ( I. 31 ) ...

Then the

**rectangle**contained by AB , BC , together with that contained by AB , AC, shall be equal to the square on AB . A D F E Construction . Upon AB describe

the square ADEB ( I. 46 ) , and through C draw CF parallel to AD or BE ( I. 31 ) ...

Side 67

The

contained by AB , BC , for it is contained by AB , BE , of which BE is equal to BC ;

and 3. AD is contained by AC , CB , for CD is equal to CB ( Def . 30 ) , and CE is ...

The

**rectangle**AE is equal to the**rectangles**AD , CE . And 2. AE is the**rectangle**contained by AB , BC , for it is contained by AB , BE , of which BE is equal to BC ;

and 3. AD is contained by AC , CB , for CD is equal to CB ( Def . 30 ) , and CE is ...

Side 68

Therefore 11. The figures HF , CK are the squares on AC , CB . And because the

complement AG is equal to the complement GE ( I. 43 ) , and that 12. AG is the

Therefore 11. The figures HF , CK are the squares on AC , CB . And because the

complement AG is equal to the complement GE ( I. 43 ) , and that 12. AG is the

**rectangle**contained by AC , CB ; for GC is equal to CB ; therefore also 13.### Hva folk mener - Skriv en omtale

Vi har ikke funnet noen omtaler på noen av de vanlige stedene.

### Andre utgaver - Vis alle

The Elements of Euclid, Containing the First Six Books, with a Selection of ... Euclides Ingen forhåndsvisning tilgjengelig - 2016 |

### Vanlige uttrykk og setninger

ABCD AC is equal alternate angle ABC angle ACB angle BAC base base BC bisected centre circle ABC circumference common compounded constr Construction contained Demonstration describe diameter divided double draw equal angles equiangular equimultiples exterior angle extremities fall figure four fourth given point given straight line greater half inscribed interior join less Let ABC likewise magnitudes manner meet multiple opposite angle parallel parallelogram pass perpendicular plane polygon Problem produced proportionals proved Q.E.D. PROPOSITION ratio reason rectangle rectangle contained rectilineal figure remaining angle right angles segment shown sides similar square square on AC taken third touches the circle triangle ABC unequal wherefore whole

### Populære avsnitt

Side 4 - If a straight line meets two straight lines, so as to make the two interior angles on the same side of it taken together less than two right angles...

Side 230 - If two triangles, which have two sides of the one proportional to two sides of the other, be joined at one angle, so as to have their homologous sides parallel to one another, the remaining sides shall be in a straight line. Let...

Side 110 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.

Side 207 - ... triangles which have one angle in the one equal to one angle in the other, and their sides about the equal angles reciprocally proportional, are equal to one another.

Side 267 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.

Side 197 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Side 21 - If two triangles have two angles of the one equal to two angles of the other, each to each, and also one side of the one equal to the corresponding side of the other, the triangles are congruent.

Side 61 - If a straight line be divided into two equal, and also into two unequal parts, the squares on the two unequal parts are together double of the square on half the line and of the square on the line between the points of section. Let the straight line AB be divided into two equal parts...

Side 30 - ... twice as many right angles as the figure has sides ; therefore all the angles of the figure together with four right angles, are equal to twice as many right angles as the figure has sides.