## The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books are Corrected, and Some of Euclid's Demonstrations are Restored. Also, the Book of Euclid's Data, in Like Manner Corrected. viz. the first six books, together with the eleventh and twelfth |

### Inni boken

Resultat 1-5 av 9

Side 41

BG is equal to A ; and in like manner the

therefore the

contained by A , BD , and by A , DE ; and also by A , EC . Wherefore , if there be

two ...

BG is equal to A ; and in like manner the

**rectangle**EH is contained by A , EC :therefore the

**rectangle**contained by A , BC is equal to the several**rectangles**contained by A , BD , and by A , DE ; and also by A , EC . Wherefore , if there be

two ...

Side 86

it in the point C , so that the

from the centre A , at the distance AB , describe the circle BDE , in which place ( 1

. 4. ) the straight line BD is equal to AC , which is not greater than the diameter ...

it in the point C , so that the

**rectangle**AB , BC be equal to the square of CA ; andfrom the centre A , at the distance AB , describe the circle BDE , in which place ( 1

. 4. ) the straight line BD is equal to AC , which is not greater than the diameter ...

Side 154

BA to AD , so is EA to AC ; and consequently the

6. ) to the ... The

in a circle , is equal to both the

BA to AD , so is EA to AC ; and consequently the

**rectangle**BA , AC is equal ( 16.6. ) to the ... The

**rectangle**contained by the diagonals of a quadrilateral inscribedin a circle , is equal to both the

**rectangles**contained by its opposite sides . Side 268

Let AB be the given straight line , and let the square upon the given straight line

C be that to which the

and draw BE at right angles to it , so that BE be equal to C ; and having joined DE

...

Let AB be the given straight line , and let the square upon the given straight line

C be that to which the

**rectangle**to be applied must be equal . Bisect AB in D ,and draw BE at right angles to it , so that BE be equal to C ; and having joined DE

...

Side 269

equal to the

which H was required is done : but if M м L N EG , GL be unequal , EG must A B

be the greater : and therefore the circle EHF cuts the straight Q Р О line AB : let it

cut ...

equal to the

**rectangle**EA , AH , that is , to the given**rectangle**C , D ; and thatwhich H was required is done : but if M м L N EG , GL be unequal , EG must A B

be the greater : and therefore the circle EHF cuts the straight Q Р О line AB : let it

cut ...

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The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ... Euclid,Robert Simson Uten tilgangsbegrensning - 1825 |

The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ... Euclid Uten tilgangsbegrensning - 1892 |

### Vanlige uttrykk og setninger

added altitude angle ABC angle BAC base centre circle circle ABCD circumference common cone contained cylinder definition demonstrated described diameter divided double draw drawn equal equal angles equiangular equimultiples Euclid excess fore four fourth given angle given in position given in species given magnitude given ratio given straight line gles greater Greek half join less likewise manner meet multiple Note opposite parallel parallelogram pass perpendicular plane prism produced PROP proportionals proposition pyramid Q. E. D. PROP radius reason rectangle rectangle contained rectilineal figure remaining right angles segment shown sides similar sine solid solid angle sphere square square of AC taken THEOR third triangle ABC wherefore whole

### Populære avsnitt

Side 45 - Ir a straight line be divided into any two parts, four times the rectangle contained by the whole line, and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.

Side 41 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.

Side 54 - Ir any two points be taken in the circumference of a circle, the straight line which joins them shall fall within the circle. Let ABC be a circle, and A, B any two points in the circumference ; the straight line drawn from A to B shall fall within the circle.

Side 18 - ABD, the less to the greater, which is impossible ; therefore BE is not in the same straight line with BC.

Side 10 - From a given point to draw a straight line equal to a given straight line. Let A be the given point, and BC the given straight line: it is required to draw from the point A a straight line equal to BC.

Side 8 - Let it be granted that a straight line may be drawn from any one point to any other point.

Side 256 - Again ; the mathematical postulate, that " things which are equal to the same are equal to one another," is similar to the form of the syllogism in logic, which unites things agreeing in the middle term.

Side 129 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Side 23 - At a given point in a given straight line, to make a rectilineal angle equal to a given rectilineal angle. Let AB be the given straight line, and A...

Side 20 - ANY two angles of a triangle are together less than two right angles.