Plane GeometryH. Holt, 1915 - 223 sider |
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Resultat 1-5 av 48
Side 1
... square , or draftsman's triangle ( Figs . 1 and 2 ) . 2. Test of a straightedge . Through two conven- ient points A and B , trace a line on a sheet of paper or other flat surface , using the edge of the ruler , or other instrument to be ...
... square , or draftsman's triangle ( Figs . 1 and 2 ) . 2. Test of a straightedge . Through two conven- ient points A and B , trace a line on a sheet of paper or other flat surface , using the edge of the ruler , or other instrument to be ...
Side 23
... square in connection with a drafting board ( see Fig . 1 , p . 1 ) or a draftsman's triangle ( see Fig . 29 ) . 81. Two straight lines which are parallel to the same straight line are parallel to each other . FIG . 29 . For , if they ...
... square in connection with a drafting board ( see Fig . 1 , p . 1 ) or a draftsman's triangle ( see Fig . 29 ) . 81. Two straight lines which are parallel to the same straight line are parallel to each other . FIG . 29 . For , if they ...
Side 25
... are based on " the square net , " that is , a series of parallel lines equal distances apart , crossed by a like series of parallels at right angles to the first . MORE ABOUT THE CIRCLE . TANGENTS 86. In § 44 PARALLELS 25.
... are based on " the square net , " that is , a series of parallel lines equal distances apart , crossed by a like series of parallels at right angles to the first . MORE ABOUT THE CIRCLE . TANGENTS 86. In § 44 PARALLELS 25.
Side 46
... square alone . 5. Given two equal circles tangent at a point P. Prove that any line segment having its extremities on the circles and passing through P is bisected by the latter . 6. Given a straight line AB and a point O not on AB ...
... square alone . 5. Given two equal circles tangent at a point P. Prove that any line segment having its extremities on the circles and passing through P is bisected by the latter . 6. Given a straight line AB and a point O not on AB ...
Side 89
... square . Hence , a square is also a rhombus which has a right angle . 243 . EXERCISES 1. The diagonals of a parallelogram bisect each other . Prove by congruent triangles . A B ΔΑΟΒΞΔ COD . A C B C 2. In the parallelogram ABCD , BE and ...
... square . Hence , a square is also a rhombus which has a right angle . 243 . EXERCISES 1. The diagonals of a parallelogram bisect each other . Prove by congruent triangles . A B ΔΑΟΒΞΔ COD . A C B C 2. In the parallelogram ABCD , BE and ...
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Plane Geometry (Classic Reprint) Chair of International History John W Young,John W. Young Ingen forhåndsvisning tilgjengelig - 2018 |
Vanlige uttrykk og setninger
acute angle adjacent angles adjacent sides altitude angle ABC angles formed base bisects called central angles chord circle with center circumscribed coincides construct a triangle convex polygon COROLLARY corresponding cosine describe a circle diagonal diameter distance divide Draw equal angles equal sides equiangular polygon equilateral triangle EXERCISES exterior angle exterior tangents feet Find the area FUNDAMENTAL PROPOSITION geometry given circle given line segment given point given straight line given triangle hypotenuse inches included angle inscribed intersecting isosceles trapezoid isosceles triangle Let the student mid-point number of sides opposite sides parallel lines parallelogram perimeter plane PROBLEM quadrilateral radian radii radius ratio rectangle regular polygon rhombus right angle right triangle rotate segment joining subtended symmetric with respect tangent THEOREM third side transversal trapezoid triangle ABC triangle are equal vertex vertices
Populære avsnitt
Side 203 - In any triangle the square of any side is equal to the sum of the squares of the other two sides minus twice the product of these two sides and the cosine of their included angle.
Side 66 - Two triangles are congruent if two sides and the included angle of the one are equal, respectively, to two sides and the included angle of the other.
Side 63 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 184 - If from a point without a circle a secant and a tangent are drawn, the tangent is the mean proportional between the whole secant and its external segment.
Side 80 - ... the angle opposite the third side of the first triangle is greater than the angle opposite the third side of the second.
Side 162 - The line which joins the mid-points of two sides of a triangle is parallel to the third side and equal to one half of it.
Side 168 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Side 179 - If two polygons are composed of the same number of triangles, similar each to each and similarly placed, the polygons are similar.
Side 183 - If two chords intersect in a circle, the product of the segments of one is equal to the product of the segments of the other.