Practical HydraulicsE. & F. N. Spon, Limited, 1882 - 80 sider |
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Side 16
... given discharge will require 100 times the head , & c . , & c . Thus , with 100 gal- lons , the Table shows that a 5 - inch pipe requires 01317 foot head per yard , then with 1000 gallons the head 16 FRICTION OF LONG PIPES .
... given discharge will require 100 times the head , & c . , & c . Thus , with 100 gal- lons , the Table shows that a 5 - inch pipe requires 01317 foot head per yard , then with 1000 gallons the head 16 FRICTION OF LONG PIPES .
Side 17
... foot ; and with 10 gallons ⚫01317 100 = 0001317 foot . The application of this principle to any case in practice is very simple : say we require the head for 33 gallons with a 24 - inch pipe 600 yards long . Not finding 33 gallons in ...
... foot ; and with 10 gallons ⚫01317 100 = 0001317 foot . The application of this principle to any case in practice is very simple : say we require the head for 33 gallons with a 24 - inch pipe 600 yards long . Not finding 33 gallons in ...
Side 18
... foot ; and the head due to velocity by Table 2 is 6 inches , or 5 foot , being more than that due to friction ; so that the total head is 392 +5 = .892 foot . pipe , the head is given and ( 13. ) When , with a very short the discharge ...
... foot ; and the head due to velocity by Table 2 is 6 inches , or 5 foot , being more than that due to friction ; so that the total head is 392 +5 = .892 foot . pipe , the head is given and ( 13. ) When , with a very short the discharge ...
Side 19
... foot , and the head for velocity is , by Table 2 , about 4 inches , or 333 foot , making a total of 08265 + · 333 = · 41565 foot , instead of 10 feet , the head at disposal . Then applying the law just given , we have 1000 × √ 10 1000 ...
... foot , and the head for velocity is , by Table 2 , about 4 inches , or 333 foot , making a total of 08265 + · 333 = · 41565 foot , instead of 10 feet , the head at disposal . Then applying the law just given , we have 1000 × √ 10 1000 ...
Side 20
... foot run , the velocity of discharge will be 62 30 = 1.2 800 1.2 x 60 = 11.1 feet per second . To find Ꭱ ( 12 ) 3 , 3 or in our case 3 we have = ⚫3333 . 9 Then the log . of 3333 = 1.522835 7 2 ) 4.659845 3 7 2.329922 = .02137 = Then ...
... foot run , the velocity of discharge will be 62 30 = 1.2 800 1.2 x 60 = 11.1 feet per second . To find Ꭱ ( 12 ) 3 , 3 or in our case 3 we have = ⚫3333 . 9 Then the log . of 3333 = 1.522835 7 2 ) 4.659845 3 7 2.329922 = .02137 = Then ...
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100 gallons 8-inch pipe 80 feet head aperture bends border in feet cloth Coef crown 8vo cubic feet cubic foot culverts Diameter of Pipe discharged per minute due to velocity Engineers Fcap feet per minute feet per second following rule foot gallons discharged gallons per inch gallons per minute gives head at disposal head due head for friction head for velocity HEAD OF WATER height of jet hydraulic radius illustrations inches diameter inches head Inches of Mercury inches overflow inches per mile Jet in Feet JET IN INCHES length loss of head maximum mean velocity nozzle parabola PIPE IN INCHES pressure Prony's rule proportions ratio require the discharge say we require SPON square feet square inch Table 15 Table 30 tank thickness total head true discharge trumpet-mouth velocity at entry Velocity in Feet velocity of discharge WATER IN FEET weir Witley Court yards long
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